Answer:
f = 409.6 Hz, the woman hears a higher frequency sound
Explanation:
This is a Doppler effect problem, which is described by the equation for the case of a fixed observer
f = fo
where the negative sign is for the source approaching the observer
in this case the car is the one that emits the sound and moves away from the intersection
let's calculate
f = 400
f = 409.6 Hz
therefore the woman hears a higher frequency sound
Answer:
E = 389 MeV
Explanation:
The total energy of particle A, will be equal to the sum of rest mass energy and relative energy of particle A. Therefore,
Total Energy of A = E = Rest Mass Energy + Relative Energy
Using Einstein's Equation: E = mc²
E = m₀c² + mc²
From Einstein's Special Theory of Relativity, we know that:
m = m₀/[√(1-v²/c²)]
Therefore,
E = m₀c² + m₀c²/[√(1-v²/c²)]
E = m₀c²[1 + 1/√(1-v²/c²)]
where,
m₀c² = rest mass energy = 140 MeV
v = relative speed = 0.827 c
Therefore,
E = (140 MeV)[1 + 1/√(1 - (0.827c)²/c²)]
E = (140 MeV)(2.78)
<u>E = 389 MeV</u>
In series, you just add them: R1 + R2 + R3 = Total R