Answer:
(a) 10 m/s
(b) 22.4 m/s
Explanation:
(a) Draw a free body diagram of the car when it is at the top of the loop. There are two forces: weight force mg pulling down, and normal force N pushing down.
Sum of forces in the centripetal direction (towards the center):
∑F = ma
mg + N = mv²/r
At minimum speed, the normal force is 0.
mg = mv²/r
g = v²/r
v = √(gr)
v = √(10 m/s² × 10.0 m)
v = 10 m/s
(b) Energy is conserved.
Initial kinetic energy + initial potential energy = final kinetic energy
½ mv₀² + mgh = ½ mv²
v₀² + 2gh = v²
(10 m/s)² + 2 (10 m/s²) (20.0 m) = v²
v = 22.4 m/s
Answer:
<h2>30 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question
force = 6 N
distance = 5 m
We have
workdone = 6 × 5 = 30
We have the final answer as
<h3>30 J</h3>
Hope this helps you
Answer:
3000 newton force is required
Explanation:
F = ma
F= 1000 kgs x 3 m/s^ 2
F=3000(kgs x m/s^2)
F=3000 newton
Answer:
24kgm/s
Explanation:
Given parameters:
Force = 80N
Mass of object = 6kg
Initial velocity = 4m/s
Final velocity = 8m/s
Solution:
Impulse = ?
Solution:
The impulse on a body is its change in momentum.
Impulse = m (v - u )
m is the mass
v is the final velocity
u is the initial velocity
Now insert the parameters and solve;
Impulse = 6 (8 - 4) = 24kgm/s
