The constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².
<h3> Constant angular acceleration</h3>
Apply the following kinematic equation;
ωf² = ωi² - 2αθ
where;
- ωf is the final angular velocity when the centrifuge stops = 0
- ωi is the initial angular velocity
- θ is angular displacement
- α is angular acceleration
ωi = 3400 rev/min x 2π rad/rev x 1 min/60s = 356.05 rad/s
θ = 52 rev x 2π rad/rev = 326.7 rad
0 = ωi² - 2αθ
α = ωi²/2θ
α = ( 356.05²) / (2 x 326.7)
α = 194.02 rad/s²
Thus, the constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².
Learn more about angular acceleration here: brainly.com/question/25129606
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Answer:
Resonance structures have <u> </u><u>same</u><u> </u> connectivity of atoms and <u> differ only in</u> distribution of electrons.
Explanation:
Atoms supply the electrons from their outer electron shells. Electrons are found free in nature and are grouped around the nucleus into shells. Electrons can be further explained as negatively charged subatomic particle. Electrons have properties of both particles and waves and they can be moved around.
Resonance structures are imaginary structures and not all of them are created equally. Resonance structures have two or more possible electron structures, and, the resonance structures for a particular substance sometimes have different energy and stability. When resonance structures are identical, they are important descriptions of the molecule. The position of the atoms is the same in the various resonance structures of a compound, but the electrons are distributed differently around the structure.
We know that the Delta E + W(Work done by non-conservative
forces) = 0 (change of energy)
In here, the non-conservative force is the friction force
where f = uN (u =kinetic friction coefficient)
W= f x d = uNd ; N=mg
Delta E = 1/2 mV^2 -1/2mVi^2
umgd + 1/2mV^2 - 1/2mVi^2 = 0 (cancel out the m term)
This will then give us:
1/2Vi^2-ugd = 1/2V^2
V^2 = Vi^2 - 2ugd
So plugging in our values, will give us:
V= Sqrt (5.6^2 -2.3^2)
=sqrt (26.07)
= 5.11 m/s
Answer:
cross out the false piece in blue and write the true piece in red
