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tia_tia [17]
3 years ago
10

In AA&E storage facilities, why must drainage structures be secured if they cross the fence line and meet certain size requi

rements?
Physics
1 answer:
Likurg_2 [28]3 years ago
6 0

Answer:

As an additional security measure in an AA&E storage facilities, securing drainage structures  must be considered if their cross section is greater than 96 inches  and any dimension is greater  than 6 inches, they must be  barred and welded at the  intersections to prevent any  human from crawling into the  area.

Explanation:

U.S. national security relys on ensuring DoD sensitive or classified assets such as classified material, arms, ammunition, and explosives  (AA&E) and nuclear weapons, in properly safeguard facilites and storage containers, voiding DoD assets loss or  compromise and additional to supplemental intrusion detection systems and guard patrols, security lighting, communications, fences and clear zones, drainage structures, key control, and other security measures required to protect  AA&E.

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What is the value for the kinetic energy for a n = 5 Bohr orbit electron in zeptoJoules?
Ne4ueva [31]

Answer:

The kinetic energy is 86.6 zepto joules.

Explanation:

Given that,

Number of orbit n =5

We know that,

Bohr's radius for hydrogen atom is

r = 0.53\times10^{-10}\times n^2\ m

Now, put the value of n in the formula of radius

r=0.53\times10^{-10}\times5^2

r =1.33\times10^{-9}\ m

We need to calculate the kinetic energy

Using formula of kinetic energy

E_{k}=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{e^2}{2\times r_{s}}

Put the value into the formula

E_{k}=\dfrac{9\times10^{9}\times(1.6\times10^{-19})^2}{2\times1.33\times10^{-9}}

E_{k}=8.66\times10^{-20}\ J

We know that,

1\ zepto\ joule=1\times10^{-21}\ J

The kinetic energy is

E_{k}=\dfrac{8.66\times10^{-20}}{1\times10^{-21}}

E_{k}=86.6\ zepto\ Joules

Hence, The kinetic energy is 86.6 zepto joules.

8 0
3 years ago
A current of 3.6-A flows through a conductor. Calculate how much charge passed through and cross-section of the conductor in 25s
Anastaziya [24]

Answer:

90 C

Explanation:

Electric current: This can be defined as the rate of flow of electric charge in a circuit. This can be expressed mathematically as,

I = dQ/dt

dQ = Idt

∫dQ = ∫Idt

Q = It................................ Equation 1

Where Q = amount of charge, I = current, t = time.

Given: I = 3.6 A, t = 25 s.

Substituting into equation 1,

Q = 3.6(25)

Q = 90 C.

Hence the amount of charge passing through the cross section of the conductor = 90 C

6 0
3 years ago
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Answer:

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Currently, the most powerful lasers reach intensities of the order of 1021W cm-2 and powers of Petawatts, PW, in each pulse. This range of intensities has opened the door for lasers to a multitude of disciplines and scientific areas traditionally reserved for accelerators and nuclear reactors, applying as generators of high-energy electron, ion, neutron and photon beams, without the need for expensive infrastructure.

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