Answer:5m
Explanation:a=-10m/s (since it moved upwards against gravity)
V=0
U=10m/s
v2=u2+2as
0= 100-20s
20s=100
s=5m
Momentum = Mass * Velocity
Total mass = 85 + 4.5 = 89.5 kg
Velocity = 2.1 m/s
Total momentum = Total Mass * Velocity
= 89.5 kg * 2.1 m/s
= 187.95 kgm/s or 187.95 Ns
Answer:
Horizontal component,
Explanation:
It is given that,
Displacement of the submarine, d = 185 m
It is at an angle of 15 degrees below the horizontal. We need to find the horizontal component of the submarine's displacement. It is given by :
Substituting the values in above equation as :
So, the horizontal component of the submarine’s displacement is 178.69 meters. Hence, this is the required solution.
Answer:
a) k = 120 N / m
n b) f = 0.84 Hz
, c) v = 1,056 m / s
, d) x=0
Explanation:
a) To find the spring constant let's use Hooke's law
F = - k x
k = -F / x
k = - 24.0 / (0.2)
k = 120 N / m
b) the angular velocity in harmonic motion is
w = √ k / m
w = √ 120 / 4.30
w = 5.28 rad / s
The angular velocity is related to the frequency
w = 2π f
f = w / 2π
f = 5.28 / 2π
f = 0.84 Hz
c) System speed is
v = dx / dt = -A w sin (wt +φ)
The speed is maximum when sin (wt + φ) = ±1
v = A w
v = 0.200 5.28
v = 1,056 m / s
d) in which position the velocity is maximum, as the velocity is a function of the sine and the position of the cosine when the sine is maximum the cosine is zero, so
x = A cos 0 = 0
x=0