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anyanavicka [17]
2 years ago
15

Number these from least (1) to most (5) inertia.

Physics
2 answers:
ale4655 [162]2 years ago
6 0
Feather, baseball, small car, truck, large train
worty [1.4K]2 years ago
5 0

Answer:

 1. A feather

2. A baseball

3. a small car

4. A truck

5. A large train

Explanation:

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When you park your car uphill next to a curb, the right front wheel should be:?
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Consider the circuit below, which is powered by a 8-v battery. switch s is opened at t = 0 after having been closed for a long t
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3 years ago
A particle (mass = 2.0 mg, charge = −6.0 μC) moves in the positive direction along the x axis with a velocity of 3.0 km/s. It en
Virty [35]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The acceleration would be  a = 0.003* 6 =0.018\  m/s^2    

Explanation:

The objective of this solution is to obtain the acceleration of the particle

       Now looking at Newton law which is mathematically represented as

                       F = ma

  Where F is the force experience by a particle

              m is the mass of the particle

              a is the acceleration of the particle

  And also this force is equivalent to magnetic force in a magnetic field which is mathematically represented as

                    F = qvB

Where q is the charge of the particle

             v is the velocity of the  charge

             B is the magnetic field the charge is under it influence

  Now equating this two formulas

                   ma = qvB

 Making a the subject we have

                  a = \frac{qvB}{m}

In the question the direction of the is in the positive x-axis which is i hence the direction would be in the i direction

      So substituting  (2.0i +3.0j+4.0k)mT = (2.0i +3.0j+4.0k)*10^{-3}T for B

                    a = \frac{q}{m} * v (2.0i +3.0j +4.0k)*10^{-3}

      Substituting       3.0 Km /s = 3.0*10^{3}\ m/s  for v  and -6.0 \muC = -6.0*10^{-6} C for q

                     a = \frac{-6.0*10^{-6}}{2.0*10^{-3}} * 3.0*10^{3} *(2i+3j+4k) *10^{-3}

                       a = 0.003 * 3i(2i+3j+4k)

                      a = 0.003 *((3*2)i \ \cdot i \ +(3*3) i \ \cdot \ j  \ + (3*4)i \ \cdot \ k)

According to vector multiplication

                                             i \cdot i = j \cdot j = k\cdot k = 1\\\\and \ i\cdot j = i\cdot k  = 0

     So

               a = 0.003* 6 =0.018\  m/s^2          

     

8 0
3 years ago
While David was riding his bike around the circular cul-de-sac by his house, he wondered if the constant circular motion was hav
RSB [31]

Answer:

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Measure the wear on his treads before and after riding a certain number of laps.

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3 years ago
Calculating Welght<br> What is the weight of a 45 kg box?<br> N
Julli [10]

Answer:

Im not sure if this is right but here is the answer i think it is....So multiply 45 by 2.205 to get 99.225 pounds. Alternately, to convert from kg to Newtons, use the fact that 1 kg is 9.8 Newtons

Explanation:

7 0
3 years ago
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