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Feliz [49]
3 years ago
15

Write the equation of a circle with a center (-3,9) and a radius of 14

Mathematics
1 answer:
babymother [125]3 years ago
4 0

Answer:

(x+3) + (y-9) = 14^2

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A circle has a sector with area 27 and central angle of 120
Alex_Xolod [135]

Answer:

81π

Step-by-step explanation:

-The sum of central angles in a  circle add up to 360°.

-Let x be the area of the circle.

-Given the area of a 120° is 27π, the circles area can be calculated as:

A=27\pi\\\\120\textdegree=27\pi\\360\textdegree=x\\\\\therefore x=\frac{360\textdegree\times 27\pi}{120\textdegree}\\\\=3\times 27\pi\\\\=81\pi

Hence, the area of the circle is 81π

6 0
3 years ago
1. -4x + 5 = 2x - 7<br> 2. 6x - 8 = 4x + 2<br> 3. -3x - 5 = 2x + 10
Svetllana [295]

Answer: 1. x=2

 2. x=5    

 3.x=-3

Isolate the variable by dividing each side by factors that don't contain the variable.

Move all terms not containing x    to the right side of the equation.

Hope this helped

7 0
3 years ago
If f(x) = 3x^2 +1 and g(x) = 1-x, what is the value of (f-g)(2)
aleksley [76]

Answer:

14

Step-by-step explanation:

Let's find (f-g)(x)

3x^{2} + 1 - (1-x)\\3x^{2} + 1 -1 + x\\3x^{2} + x

Now let's plug in x=2, so to find (f-g)(2)

3(2)^{2} + 2\\12 + 2 = 14

8 0
3 years ago
Parabolas y=−2x^2 and y=2x^2 +k intersect at points A and B that are in the third and the fourth quadrants respectively. Find k
OverLord2011 [107]

Answer:

-25  

Step-by-step explanation:

(1)   y = -2x²

(2) y =   2x² + k     Subtract (1) from (2)

    0 =  4x² + k      Subtract 4x² from each side

    k = -4x²

The parabolas are <em>symmetrical about the y-axis.</em>

Segment AB = 5, so x = +2.5 and x = +2.5.

k = -4(±2.5)² = -4 × 6.25 = -25

8 0
3 years ago
Can somebody please help me with this question
Zanzabum

Answer:

B

Step-by-step explanation:

6 0
3 years ago
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