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snow_tiger [21]
3 years ago
12

Classify each substance as a pure substance or a mixture.

Chemistry
1 answer:
Arisa [49]3 years ago
3 0

Answer:

<em />

  • <em>1) Copper is a </em><u>pure substance</u>
  • <em>2) A solution of sugar dissolved in water is a </em><u>mixture</u>
  • <em>3) Carbon dioxide is a</em><u> pure substance.</u>
  • <em>4) Seawater is a </em><u>mixture</u>
  • <em>5) Table salt is a </em><u>pure substance.</u>

Explanation:

<u><em>1) Copper, which consists of only one kind of atom</em></u>

<u><em></em></u>

There are two kind of pure substances: elements and compounds.

Substances made up of one kind of atom, like copper, are elements.

There are 118 known elements, and you can find them in any periodic table.

Copper is the element with atomic number 29.

Thus, copper is a pure substance, because it is consituted by one kind of atoms.

<em><u>2) A solution of sugar dissolved in water</u></em>

A solution consists of solute and solvent, which can be in any proportion. The solutions of sugar and water may be 1%, 2%, 15%, 98%, or any percent. Thus, a solution does not have a fixed composition and is not a pure substance. Pure substances have definite compositions.

It is a mixture of sugar (solute) and water (solvent) which constitutes a solution.

A mixture is the physical combination of two or more substances which can be in any proportion.

Therefore, a solution of sugar and water is a mixture.

<em><u>3) Carbon dioxide, which has two atoms of oxygen for each atom of carbon</u></em>

<em />

Carbon dioxide has a definite composition of two atoms of oxygen for each atom of carbon. Every molecule of carbon dioxide has the same composition.

The atoms of carbon and oxygen are chemically bonded. They cannot be separated by any physical media.

Two or more atoms chemically bonded constitute a compound, which will have a definite composition and is a pure substance.

Thus, this is a pure substance.

<u><em>4) Seawater, which can be purified by filtering it.</em></u>

Mixtures can be purified by physical media, such as filtering (among many others like evaporation or uisng magnets, if one of the substaces has magnetic properties).

Pure substaces, elements or compounds, cannot be separated by physical media.

Seawater can be purified, i.e. separated from sand grains and algae residue, for instance, by fitering because seawater is a mixture.

Yet, the "pure" seawater, i.e. the liquid that remains after filtering, will be a mixture, because it is a solution of several salts (including sodium chloride, among others) and water.

You cannot separate the pure substances from seawater by filtering. That would require a chemical process.

Therefore, seawater is a mixture.

<u><em>5) Table salt, which can be separated into sodium and chlorine only by chemical processes</em></u>

<u><em></em></u>

The fact that the table salt can be separated into sodium and chlorine only by chemical processes indicates that it is a pure substance.

Table salt is the ionic compound NaCl

NaCl has a definite composition: every crystal of salt will have many NaCl units. Every NaCl unit is equal to any other NaCl unit: one atom of Na is chemically bonded to one atom of Cl.

The chemical bonds cannot be broken by physical media; a chemical process is required, and the formed substances will have completely different properties than the original compound.

Hence, table salt is a pure substance (a compound).

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Chloroform, CHCl3, reacts with chlorine, Cl2, to form carbon tetrachloride, CCl4, and hydrogen chloride, HCl. In an experiment 2
erastovalidia [21]

Answer:

Chloroform= limiting reactant

0.209mol of CCl4 is formed

And 32.186g of CCl4 is formed

Explanation:

The equation of reaction

CHCl3 + Cl2= CCl4 + HCl

From the equation 1 mol of

CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4

From the question

25g of CHCl3 really with Cl2

Molar mass of CHCl3= 119.5

Molar mass of Cl2 = 71

Hence moles of CHCl3= 25/119.5 = 0.209mol

Moles of Cl2 = 25/71 = 0.352mol

Hence CHCl3 is the limiting reactant

Since 1 mole of CHCl3 gave 1mol of CCl4

It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4

Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g

6 0
4 years ago
In Haber’s process, 30 moles of hydrogen and 30 moles of nitrogen react to make ammonia. If the yield of the product is 50%, wha
devlian [24]

Answer:

Therewill be produced 170.6 grams NH3, there will remain 25 moles of N2, this is 700 grams

Explanation:

<u>Step 1:</u> Data given

Number of moles hydrogen = 30 moles

Number of moles nitrogen = 30 moles

Yield = 50 %

Molar mass of N2 = 28 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass of NH3 = 17.03 g/mol

<u>Step 2:</u> The balanced equation

N2 + 3H2 → 2NH3

<u>Step 3:</u> Calculate limiting reactant

For 1 mol of N2, we need 3 moles of H2 to produce 2 moles of NH3

Hydrogen is the limiting reactant.

The 30 moles will be completely be consumed.

N2 is in excess. There will react 30/3 =10 moles

There will remain 30 -10 = 20 moles (this in the case of a 100% yield)

In a 50 % yield, there will remain 20 + 0,5*10 = 25 moles. there will react 5 moles.

<u>Step 4:</u> Calculate moles of NH3

There will be produced, 30/ (3/2) = 20 moles of NH3 (In case of 100% yield)

For a 50% yield there will be produced, 10 moles of NH3

<u>Step 5</u>: Calculate the mass of NH3

Mass of NH3 = mol NH3 * Molar mass NH3

Mass of NH3 = 20 moles * 17.03

Mass of NH3 = 340.6 grams = theoretical yield ( 100% yield)

<u>Step 6: </u>Calculate actual mass

50% yield = actual mass / theoretical mass

actual mass = 0.5 * 340.6

actual mass = 170.3 grams

<u>Step 7:</u> The mass of nitrogen remaining

There remain 20 moles of nitrogen + 50% of 10 moles = 25 moles remain

Mass of nitrogen = 25 moles * 28 g/mol

Mass of nitrogen = 700 grams

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Animal cells have centrosome and centrioles.

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