Coastal waves dissolving limestone sediments

A compound with molecular formula C5H10O2 has the following 1H NMR spectrum: 1.15 (t, 3H), 1.25 (t, 3H), 2.33 (q, 2H), 4.13 (q,

Vilka [71]

Answer:

Ethyl propionate

Explanation:

Calculating the double bond equivalence as:

DBE = C - (H/2) - (X/2) + (N/2) +1

Where

C is the number of carbon atoms

N is the number of nitrogen atoms

X is the number of halogens

H is the number of hydrogen atoms

So, according to the formula, $C_5H_{10}O_2$

DBE = 5 - (10/2) - (0/2) + (0/2) +1 = 1

It means there is one double bond or one ring.

from the NMR signal, it is clear that compound has two triplet and two quardrate group that means two -CH3 and two -CH2 groups are present.

From the splitting information, it is clear that each the -CH2- group is next to a -CH3, and vice-versa. In this case ring structure is not possible.

The chemical shift of two protons 4.13 ppm(q, 2H) is for protons next to an O atom, therefore, compound must have

$-OCH_2CH_3$ .

Then the signal at 2.33 is for a -CH2-group next to a C=O. So compound must have a structure CH3-CH2-C=O. Now, there is only one way to complete the structure - by bonding the O to the C=O carbon.

So the compound is ethyl propionate

3 0

3 years ago

The most common use of the ammonia manufactured is in A. fertilizers for crops. B. plastics manufacturing. C. household cleaners

Katena32 [7]

A fertilizer for crops

5 0

3 years ago

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According to the lewis dot structure shown here, how many valence electrons does chlorine have?

777dan777 [17]

Chlorine atom has 17 electrons. It has seven valence electrons. These seven electrons make chlorine a very reactive element. A valence electron is an electron that is associated with an atom, and that can participate in the formation of a chemical bond. Hope this helps.

8 0

3 years ago

The gas cyclobutane, C4H8(g), can be used in welding. When cyclobutane is burned in oxygen, the reaction is: C4H8(g) + 6 O2(g)4

Snowcat [4.5K]

Answer:

a

$\Delta H^o _{rxn} = -2568.9 \ kJ$

b

$H = 350 JK^{-1}$

c

$T_{max} = 32.4 ^o C$

Explanation:

From the question we are told that

The reaction of cyclobutane and oxygen is

$C_4H_8_{(g)} + 6 O_2_{(g)} \to 4 CO_2_{(g)} + 4 H_2O_{(g)}$

ΔH°f (kJ mol-1) : C4H8(g) = 27.7 ; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = kJ

Generally ΔH° for this reaction is mathematically represented as

$\Delta H^o _{rxn} = [[4 * \Delta H^o_f (CO_2_{(g)} ) + 4 * \Delta H^o_f(H_2O_{(g)} ] -[\Delta H^o_f (C_2H_6_{(g)} + 6 * \Delta H^o_f (O_2_{(g)}) ] ]$

=> $\Delta H^o _{rxn} = [[4 * (-393.5) + 4 * (-241.8) ] -[ 27.7 + 6 * 0]$

=> $\Delta H^o _{rxn} = -2568.9 \ kJ$

Generally the total heat capacity of 4 mol of CO2(g) and 4 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g) = 33.6 J K-1 mol-1. C = J K-1 is mathematically represented as

$H = [ 4 * C_{CO_2_{(g)}} + 6* C_{CH_2O_{(g)}}]$

=> $H = [ 4 * 37.1 + 6* 33.6 ]$

=> $H = 350 JK^{-1}$

From the question the initial temperature of reactant is $T_i = 25^oC$

Generally the enthalpy change( $\Delta H^o _{rxn}$ ) of the reaction is mathematically represented as

$|\Delta H^o _{rxn} |= H * (T_{max} -T_i)$

$2568.9 = 350 * (T_{max} -25)$

=> $\frac{2568.9 }{350} = T_{max} - 25$

=> $T_{max} = 32.4 ^o C$

4 0

3 years ago

Why does temperature increase with altitude through the stratosphere? The stratosphere is closest to the sun. The ozone layer is

lukranit [14]

Temperature increase with altitude through the stratosphere because "The ozone layer is found in the stratosphere".

Stratosphere is the second layer of the atmosphere of the Earth. 20% of the mass of the atmosphere is found in this layer.
The temperature of the stratosphere increases as the altitude increases due to the presence of the ozone layer in it as the ozone layer absorbs the ultraviolet radiations of the Sun which causes an increase in the temperature of this layer.

8 0

3 years ago

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