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True [87]
3 years ago
15

Calculate each of the following quantities. (a) Mass (g) of solute in 175.4 mL of 0.267 M calcium acetate WebAssign will check y

our answer for the correct number of significant figures. g (b) Molarity of 597 mL solution containing 21.1 g of potassium iodide WebAssign will check your answer for the correct number of significant figures. M (c) Amount (mol) of solute in 145.6 L of 0.703 M sodium cyanide WebAssign will check your answer for the correct number of significant figures. mol
Chemistry
1 answer:
ss7ja [257]3 years ago
8 0

Answer:

a) 7.40 grams

b) 0.213 M

c) 102 moles

Explanation:

(a) Mass (g) of solute in 175.4 mL of 0.267 M calcium acetate

Step 1: Data given

Volume = 175.4 mL = 0.1754 L

Molarity = 0.267 M

Molar mass = 158.17 g/mol

Step 2: Calculate moles

Moles = molarity * volume

Moles = 0.267 M * 0.1754 L

Moles = 0.0468 moles

Step 3: Calculate mass

Mass = 0.0468 moles * 158.17 g/mol

<u>Mass = 7.40 grams</u>

b) Molarity of 597 mL solution containing 21.1 g of potassium iodide

Step 1: Data given

Volume = 597 mL = 0.597 L

Mass = 21.1 grams

Molar mass KI = 166.0 g/mol

Step 2: Calculate moles KI

Moles KI = 21.1 grams / 166.0 g/mol

Moles KI = 0.127 moles

Step 3: Calculate molarity

Molarity = moles / volume

Molarity = 0.127 moles / 0.597 L

Molarity = 0.213 M

(c) Amount (mol) of solute in 145.6 L of 0.703 M sodium cyanide

Step 1: Data given

Volume = 145.6 L

Molarity = 0.703 M

Step 2: Calculate moles

moles = molarity * volume

Moles = 0.703 M * 145.6 L

Moles = 102 moles

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Divide the moles of each reactant by its coefficient in the balanced equation, and the limiting reagent is identified as the one whose value is less. With the issue we now have...

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the gas pressure, measured in atmospheres, that is still in the flask

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0.3688......0.1764............0..........

Initial

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Equilibrium: 0.1924.......0...............+0.1924

There are 0.1924 moles of NH3 and no other gases in the flask. This is at a temperature of 25 °C (+273 = 298 °K) in a volume of 0.5 L. After that, we may determine the pressure by using the ideal gas law (P).

PV = nRT

P = nRT/V = 0.1924 mol, 0.0821 latm/mol, and 298 Kmol / 0.5 L

P = 9.41 atm

9.41 atm is the pressure in atmospheres of the gas remaining in the flask

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brainly.com/question/11904811

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