Answer : The mass of aluminium (Al) is 0.413 g
Solution : Given,
Volume of at STP = 513 ml = 0.513 L ( 1 L = 1000 ml )
Molar mass of aluminium = 26.98 g/mole
First we have to calculate the moles of .
At STP,
1 mole occupies 22.4 L volume
now, 0.513 L gives moles of
The moles of = 0.0229 moles
The Net balanced chemical reaction is,
From the balanced chemical reaction, we conclude that
2 moles of Aluminium (Al) produces 3 moles of hydrogen gas
Now the number of moles of aluminium required in 0.0229 moles of hydrogen gas = = 0.0153 moles
Now we have to calculate the mass of aluminium.
Mass of aluminium = number of moles × Molar mass = 0.0153 moles × 26.98 g/mole = 0.413 g
The mass of aluminium required is 0.413 g.
Answer:
34.8 mL
Explanation:
First we <u>convert 5.48 g of CuNO₃ into moles</u>, using its<em> molar mass</em>:
- 5.48 g CuNO₃ ÷ 187.56 g/mol = 0.0292 mol
Now we can <u>calculate the volume of the solution</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- 0.840 M = 0.0292 mol / liters
Finally we <u>convert L into mL</u>:
- 0.0348 L * 1000 = 34.8 mL
Answer:
Lowering activation energy of a reaction.
Explanation:
Activation energy is the minimum amount of energy required by the reactants just to be converted to products.
Since catalysts increase the rate of reaction, activation complex is reached in short period of time hence activation energy is lowered.