<u>Answer:</u> The mass of water required is 1.79 grams
<u>Explanation:</u>
To calculate the amount of oxygen gas, we use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 0.926 atm
V = Volume of the gas = 1.3 L
T = Temperature of the gas = 295 K
R = Gas constant =
n = number of moles of oxygen gas = ?
Putting values in above equation, we get:
For the given chemical equation:
By Stoichiometry of the reaction:
1 mole of oxygen gas is produced from 2 moles of water
So, 0.0497 moles of oxygen gas will be produced by = of water
To calculate the number of moles, we use the equation:
Moles of water = 0.0994 moles
Molar mass of water = 18 g/mol
Putting values in above equation, we get:
Hence, the mass of water required is 1.79 grams