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3 years ago

8

What does NOT affect the characteristic properties of an element?

1 answer:

bazaltina [42]3 years ago

5 0

Answer:

characteristic properties of an element are the defining properties of that element and it does not change with quantity of the element used.

Explanation:

the amount or the quantity of the element used does not affect the characteristic property of the element. it does not matter is the if the amount or the quantity of the element used in the reaction is large or the small the characteristic properties like boiling point, melting point, density, thermal conductivity, etc remain the same or remain constant.

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Q05 the "atomic number" of an atom is determined by the number of ________ it has.

Alexxx [7]

The atomic number of an atom is determined by the number of protons it has..

It is also the whole number shown on the periodic table

6 0

4 years ago

The graph below shows how the temperature and volume of a gas vary when

Sever21 [200]

Answer:

C

Explanation:

because it remains the same

3 0

3 years ago

An empty Erlenmeyer flask weighs 241.3 g. When filled with water (d = 1.00 g/cm³), the flask and its contents weigh 489.1 g.

Viefleur [7K]

The answer is- Mass of flask = 608.04 g

Density (d) is defined as mass of substance divided by its volume. Thus, if mass and density are known, then Volume can be determined.

What is the formula of mass in terms of density?

Let mass of substance be 'm' and volume be 'V'. Thus, as per the definition of density, it is expressed as-

$d = \frac{m}{V}$

Thus, mass can be expressed as-

$m = d * V$

Now, mass of empty flask = 241.3 g and the mass of (flask + Water) = 489.1 g.

Thus, mass of water = $489.1\ g- 241.3\ g = 247.8\ g$ .

Thus, mass of water = 247.8 g and density of water = $1.00\ g/cm^3$ . Its volume is calculated as-

$V = \frac{247.8\ g}{1.00\ g/cm^3}=247.8\ cm^3$

Volume of flask = 247.8 $cm^3$ .
Then when this flask is filled with chloroform (d = $1.48 g/cm^3$ ), the mass of chloroform is-

$m = d * V = (1.48\ g/cm^3) * (247.8\ cm^3)= 366.74\ g$

Hence, the mass of flask becomes = $241.3\ g + 366.74\ g = 608.04\ g$

To learn more about Density and mass, visit:

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4 0

1 year ago

Metallic aluminum reacts with MnO2 at elevated temperatures to form manganese metal and aluminum oxide. A mixture of the two rea

Oksi-84 [34.3K]

Answer:

Explanation:

To find the theoretical yield of the equation. First identify the limiting reactant in a chemical equation.

Step 1: write out the equation and balance it.

Al+ 3mno2=3mn+ 2Alo3.

The limiting reactant is mn02 because it is not found in excess.

Step 2: convert the % to gram . All contain 67.2% mole and mno2 will be 100-67.2= 32.8

All=67.2÷100×290(total gram of the reactants)=194.88g

Mno2=32.8÷100×290g=94.12g.

Step 3:calculate the molar mass of mno2 and that of mn. The atomic mass of mn is 54.9380 and that of oxygen is 16.

Mno2=54.938+ (16)2=86.98g/mol.

Mn=54.938.

Step 4:

From your balanced equation , calculate mn.

94.12g mno2× (1mol mno2÷86.98(molarmass) of mno2×3 mol of mn/4molAl×54.938g of mn÷1mol of mn.

94.12g×1÷86.98g×3÷4×54.938÷1

=44.58g

6 0

3 years ago

What is the specific heat of an object that weighs 15 grams and changes temperature from 30°C to 37°C when 50 J of heat is added

Scorpion4ik [409]

Answer:

0.4762 J/g°C.

Explanation:

It is known that:

<em>The amount of heat released to water = Q = m.c.ΔT.</em>

where, m is the mass of water (m = 15.0 g).

c is the specific heat capacity of water = ??? J/g°C.

ΔT is the temperature difference = (final T - initial T = 37.0°C - 30.0°C = 7.0°C).

<em>∴ The specific heat capacity of water = c = Q/m.ΔT</em> = (50.0 J)/(15.0 g)(7.0°C) = <em>0.4762 J/g°C.</em>

8 0

4 years ago