1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NemiM [27]
4 years ago
13

Which could be the catalyst in a chemical reaction?

Chemistry
1 answer:
elena-s [515]4 years ago
7 0
 enzyme if you use plato

You might be interested in
A certain drug has a half-life in the body of 3.5h. Suppose a patient takes one 200.Mg pill at :500PM and another identical pill
tekilochka [14]

Answer:

The amount of drug left in his body at 7:00 pm is 315.7 mg.

Explanation:

First, we need to find the amount of drug in the body at 90 min by using the exponential decay equation:

N_{t} = N_{0}e^{-\lambda t}

Where:

λ: is the decay constant = ln(2)/t_{1/2}

t_{1/2}: is the half-life of the drug = 3.5 h

N(t): is the quantity of the drug at time t

N₀: is the initial quantity

After 90 min and before he takes the other 200 mg pill, we have:

N_{t} = 200e^{-\frac{ln(2)}{3.5 h}*90 min*\frac{1 h}{60 min}} = 148.6 mg

Now, at 7:00 pm we have:

t = 7:00 pm - (5:00 pm + 90 min) = 30 min

N_{t} = (200 + 148.6)e^{-\frac{ln(2)}{3.5 h}*30 min*\frac{1 h}{60 min}} = 315.7 mg    

Therefore, the amount of drug left in his body at 7:00 pm is 315.7 mg (from an initial amount of 400 mg).

I hope it helps you!

3 0
3 years ago
A substance has a volume of 10.0 cm3 and a mass of 89 grams. What is its density?
Irina18 [472]
Remembering that
d = m ÷ v

d = ?
m = 89 g
v = 10 cm³

Therefore:

d = 89 ÷ 10

d = 8,9 g÷cm³
5 0
3 years ago
Read 2 more answers
Cellulose and starch are examples of:
mixer [17]

Answer:

The choose (d)

d. polysaccharides

3 0
3 years ago
Read 2 more answers
Which type of stoichiometry problems does not require the use of molar mass?
Arlecino [84]

Answer:

Explanation:

It is volume-volume problems that does not require the use of molar mass.

7 0
3 years ago
The reaction of 5.40 g of carbon with excess O2 yields 13.6 g of CO2. What is the percent yield of this reaction?
vazorg [7]
C + O2= CO2
n  =  \frac{m}{mw}
n =  \frac{5.4}{12}  \\ n  = 0.45 \: mol \: of \: carbon
n =  \frac{13.6}{12 + 16 \times 2} \\ n =  \frac{13.6}{44}  \\ n = 0.31 \: mol \: of \: carbon \: dioxide
CO2 is limit
5.4-3.72= 1.68 g of C is excess
5.4 g = 100%
3.72 g = x
x=68.9 %
4 0
3 years ago
Other questions:
  • When used in a shorthand electron configuration, the noble gas core [He] represents 1s^2 2s^2 2p^6.
    6·2 answers
  • Complete the passage about metallic bonding.
    9·1 answer
  • Cliffs may be affected by weathering. Describe ONE  effect of weathering on a cliff .
    12·2 answers
  • What is the common name of H2O
    8·2 answers
  • Click on the molecules that represent transpiration.
    10·1 answer
  • What is the atomic mass number ?
    11·1 answer
  • Most of the sulfur used in the United States is chemically synthesized from hydrogen sulfide gas recovered from natural gas well
    6·1 answer
  • Perform the following
    9·1 answer
  • What are the functions of nervous system​
    10·2 answers
  • A chemistry student wants to learn how pressure and volume affect one another. They gather a sample of helium from a ballon and
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!