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2 years ago

6. What symptom will be exhibited on an engine equipped with a pneumatic governor system if the cooling fins

Engineering

1 answer:

anyanavicka [17]2 years ago

8 0

<h2>Symptom of Pneumatic Governor System</h2>

Explanation:

Engine speed will rise is right answer

Pneumatic Governor system that utilizations power from moving air delivered by pivoting flywheel blades to detect engine speed
Electronic Governor System Uses a limited point torque engine in place of the governor spring and -speed-sensing device utilized in a mechanical governor system
A governor is a system that is utilized to keep up the mean speed of a engine, inside specific cutoff points, under fluctuating burden conditions
It does this by managing and controlling the measure of fuel provided to the motor
Governors are likewise fitted in assistant diesel motors or generators, and alternators on the ship

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(1.24) Consumer Reports is doing an article comparing refrigerators in their next issue. Some of the characteristics to be inclu

kondaur [170]

Answer:

“height is a quantitative variable ”

Explanation:

According to the question asked, answer is “height is a quantitative variable ”

Height is a quantitative variable because it is related to the measurement and in measurement, when we measure something we deal with number (numerical data)

Numerical data is a type of quantitative data that is why we say “height is a quantitative variable”

There are some other possible questions in the given paragraph which I would like to mention here, are as following:

Which are the categorical variables in the given report?

<u>Answer: </u>Energy star complaints

Top, Bottom or side-by-side freezer

Which are the quantitative variables in the given report?

<u>Answer:</u> Estimated Energy Consumption in kilowatts

Width, depth, and height in inches

Capacity in Cubic Feet

What are the individuals in the report?

<u>Answer: </u>The brand name and model

8 0

2 years ago

A cylindrical container is 150mm in diameter and weights 2.25n when empty

stellarik [79]

Answer:

Explanation:

3 0

2 years ago

An aluminum oxide component must not fail when a tensile stress of 12.5 MPa is applied. Determine the maximum allowable surface

aivan3 [116]

Answer:

1.44 mm

Explanation:

Compute the maximum allowable surface crack length using

$C=\frac {2E\gamma}{\pi \sigma_c^{2}}$ where E is the modulus of elasticity, $\gamma$ is surface energy and $\sigma_c$ is tensile stress

Substituting the given values

$C=\frac {2\times 393\times 10^{9}\times 0.9}{\pi\times (16\times 10^{6})^{2}= 0.001441103 m\approx 1.44mm$

The maximum allowable surface crack is 1.44 mm

4 0

3 years ago

I have a molten Ni-Cu alloy with 60 wt%Ni. (ii) I cool it down to a temperature where I have both solid and liquid phases. At th

SIZIF [17.4K]

Answer:

The percentage of the remaining alloy would become solid is 20%

Explanation:

Melting point of Cu = 1085°C

Melting point of Ni = 1455°C

At 1200°C, there is a 30% liquid and 70% solid, the weight percentage of Ni in alloy is the same that percentage of solid, then, that weight percentage is 70%.

The Ni-Cu alloy with 60% Ni and 40% Cu, and if we have the temperature of alloy > temperature of Ni > temperature of Cu, we have the follow:

60% Ni (liquid) and 40% Cu (liquid) at temperature of alloy

At solid phase with a temperature of alloy and 50% solid Cu and 50% liquid Ni, we have the follow:

40% Cu + 10% Ni in liquid phase and 50% of Ni is in solid phase.

The percentage of remaining alloy in solid is equal to

Solid = (10/50) * 100 = 20%

4 0

3 years ago

A particle moves along a straight line such that its position is defined by s = (t2 - 6t + 5) m. Determine the average velocity,

Dominik [7]

Answer:

0 m/s , 3 m/s , 2 m/s^2

Explanation:

Given : s(t) = ( t^2 - 6t + 5)

v(t) = ds / dt = 2t - 6

s(0) = 5 m

s(6) = (6)^2 - 6*6 + 5 = 5 m

Vavg = ( s(6) - s(0) ) / 2 = 0 m\s

Find the turning point of particle:

ds/dt = 0 = 2t - 6

t = 3 sec

s(3) = 3^2 -6*3 + 5 = - 4

Total distance = 5 - (-4) + (5 - (-4)) = 18 m

Total time = 6s

Average speed = Total distance / Total time = 18 / 6 = 3 m/s

Taking derivative of v(t) to obtain a(t)

a (t) = dv(t) / dt = 2 m/s^2

7 0

2 years ago