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3 years ago

6. What symptom will be exhibited on an engine equipped with a pneumatic governor system if the cooling fins

Engineering

1 answer:

anyanavicka [17]3 years ago

8 0

<h2>Symptom of Pneumatic Governor System</h2>

Explanation:

Engine speed will rise is right answer

Pneumatic Governor system that utilizations power from moving air delivered by pivoting flywheel blades to detect engine speed
Electronic Governor System Uses a limited point torque engine in place of the governor spring and -speed-sensing device utilized in a mechanical governor system
A governor is a system that is utilized to keep up the mean speed of a engine, inside specific cutoff points, under fluctuating burden conditions
It does this by managing and controlling the measure of fuel provided to the motor
Governors are likewise fitted in assistant diesel motors or generators, and alternators on the ship

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A refrigerator has a cooling load of 50 kW. It has a COP of 2. It is run by a heat engine which consumes 50 kW of heat to supply

Sunny_sXe [5.5K]

Answer:

50%

Explanation:

<u>Given information</u>

Cooling load=50 kW

COP=2

Consumption=50 kW

<u>Calculations</u>

Revised input is given by cooling load/COP=50/2=25 kW

Efficiency= Work output/ Revised input=25/50=0.5

Efficiency=0.5*100=50%

8 0

3 years ago

A bar of 75 mm diameter is reduced to 73mm by a cutting tool while cutting orthogonally. If the mean length of the cut chip is 7

barxatty [35]

Answer:

r=0.31

Ф=18.03°

Explanation:

Given that

Diameter of bar before cutting = 75 mm

Diameter of bar after cutting = 73 mm

Mean diameter of bar d= (75+73)/2=74 mm

Mean length of uncut chip = πd

Mean length of uncut chip = π x 74 =232.45 mm

So cutting ratio r

$Cutting\ ratio=\dfrac{Mean\ length\ of cut\ chip}{Mean\ length\ of uncut\ chip}$

$r=\dfrac{73.5}{232.45}$

r=0.31

So the cutting ratio is 0.31.

As we know that shear angle given as

$tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }$

Now by putting the values

$tan\phi =\dfrac{rcos\alpha }{1-rsin\alpha }$

$tan\phi =\dfrac{0.31cos15 }{1-0.31sin15 }$ \

Ф=18.03°

So the shear angle is 18.03°.

4 0

4 years ago

Why do you suppose a value of 5 is used? Do you think other values might work?

Shtirlitz [24]

Answer:

YES

Explanation:

values other than five will work

3 0

3 years ago

What is the role of the architects in modern development

pshichka [43]

Answer:

to plan, design, and oversee the construction of a building

7 0

3 years ago

A square loop of wire surrounds a solenoid. The side of the square is 0.1 m, while the radius of the solenoid is 0.025 m. The sq

Semmy [17]

Answer:

I=9.6×e^{-8} A

Explanation:

The magnetic field inside the solenoid.

B=I*500*muy0/0.3=2.1×e ^-3×I.

so the total flux go through the square loop.

B×π×r^2=I×2.1×e^-3π×0.025^2

=4.11×e^-6×I

we have that

(flux)'= -U

so differentiating flux we get

so the inducted emf in the loop.

U=4.11×e^{-6}×dI/dt=4.11×e^-6×0.7=2.9×e^-6 (V)

so, I=2.9×e^{-6}÷30

I=9.6×e^{-8} A

6 0

3 years ago