Answer:
A
Hope this helps!
Explanation:
You need to find what the problem is and what can or can not be done to solve that issue/compete the task
In a slowly cooled hypereutectoid iron-carbon steel, the pearlite colonies are normally separated from each other by a more or less continuous boundary layer of cementite done by Slower cooling reasons coarse Pearlite, even as rapid cooling reasons first-rate pearlite to form.
<h3>What levels is in Hypereutectoid metal?</h3>
Hypoeutectoid steels can, upon preliminary cooling from the austenite single segment field, exist as extraordinary levels, eutectoid ferrite and austenite, every with extraordinary carbon contents.
At room temperature, hypereutectoid steels have a pearlitic primary microstructure (ferrite grains with embedded cementite lamellae) with moreover induced cementite on the grain boundaries! The micrograph under suggests a hypereutectoid metal with 1.0 Carbon (C100).
Read more about the cementite:
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Answer:
1. All engines exhibit wear over time ⇒ <em>Synthetic Improves engine protection by resisting oil breakdown.</em>
Synthetic oil does not breakdown so easily which means that it protects the engine more and protects it from wearing.
2. Engines are cold at start-up and not while running ⇒ <em> Synthetic provides maximum protection in extreme hot and cold temperature conditions.</em>
By providing protection for the engine during cold and hot conditions, the engine will not be too cold when the car is started up.
3. If oil is thicker, engines lose power and efficiency ⇒ <em>Synthetic has greater resistance to oil thickening to maintain engine efficiency.</em>
Part of the characteristics of synthetic oil is that it does not get as thick as regular oil which means that the adverse effects of thick oil are spared on the engine.
Answer:
Concentration factor will be 1.2
So option (C) will be correct answer
Explanation:
We have given outer diameter D = 1.25 in
And inner diameter d = 1 in and fillet ratio r = 0.2 in
So 
ratio will be 
And 
ratio will be 
Now from the graph in shaft vs torsion the value of concentration factor will be 1.2
So concentration factor will be 1.2
So option (C) will be correct answer.
Answer:
Explanation:
Hello!
To solve this problem you must follow the following steps, which are fully registered in the attached image.
1. Draw the complete outline of the problem.
2. Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)
through prior knowledge of two other properties.
3. Use temodynamic tables to find the density of water in state 1, by means of temperature and quality, with this value and volume we can find the mass.
3. Use thermodynamic tables to find the internal energy in state 1 and two using temperature and quality.
4. uses the first law of thermodynamics that states that the energy in a system is always conserved, replaces the previously found values and finds the work done.
5. draw the pV diagram using the 300F isothermal line
