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Free_Kalibri [48]

3 years ago

6

Select the correct answer.

1 answer:

cricket20 [7]3 years ago

5 0

Answer:

A.

The power generated by a wind farm is not constant because of irregular wind patterns.

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True or False? A constricting nozzle is used

marissa [1.9K]

Answer:

True

Explanation:

Principles of plasma arc cutting, Uses a constricting nozzle to create, concentrate, and direct the high-velocity plasma. Plasma gas is always used

in plasma arc cutting When shielding gas is also used, the process is called dual flow plasma arc cutting. I hope this helps.

6 0

4 years ago

Translating type screws are used: A. In translating machines B. For imparting motion to a mechanical part C. As a fastener to co

ivanzaharov [21]

Answer:

(b) for imparting motion to a mechanical part

Explanation:

a screw is a made of metal material usually hard metal it is mainly consist of a head at one end and a point at other end it also consist a shaft by virtue of which it can be change into other material there are many type of screw present translating type is one of them which is mostly use for imparting motion to a mechanical part

4 0

4 years ago

Measures the power output of the machine

koban [17]

Watts I believe is the answer

4 0

3 years ago

Using OOP, write a C++ program that will read in a file of names. The file is called Names.txt and should be located in the curr

Tanzania [10]

Not really sure sorry for not being able to help

5 0

3 years ago

Read 2 more answers

A group of students launches a model rocket in the vertical direction. Based on tracking data, they determine that the altitude

Fofino [41]

Answer:

$u = 260.22m/s$

$S_{max} = 1141.07ft$

Explanation:

Given

$S_0 = 89.6ft$ --- Initial altitude

$S_{16.5} = 0ft$ -- Altitude after 16.5 seconds

$a = -g = -32.2ft/s^2$ --- Acceleration (It is negative because it is an upward movement i.e. against gravity)

Solving (a): Final Speed of the rocket

To do this, we make use of:

$S = ut + \frac{1}{2}at^2$

The final altitude after 16.5 seconds is represented as:

$S_{16.5} = S_0 + ut + \frac{1}{2}at^2$

Substitute the following values:

$S_0 = 89.6ft$ $S_{16.5} = 0ft$ $a = -g = -32.2ft/s^2$ and $t = 16.5$

So, we have:

$0 = 89.6 + u * 16.5 - \frac{1}{2} * 32.2 * 16.5^2$

$0 = 89.6 + u * 16.5 - \frac{1}{2} * 8766.45$

$0 = 89.6 + 16.5u- 4383.225$

Collect Like Terms

$16.5u = -89.6 +4383.225$

$16.5u = 4293.625$

Make u the subject

$u = \frac{4293.625}{16.5}$

$u = 260.21969697$

$u = 260.22m/s$

Solving (b): The maximum height attained

First, we calculate the time taken to attain the maximum height.

Using:

$v=u + at$

At the maximum height:

$v =0$ --- The final velocity

$u = 260.22m/s$

$a = -g = -32.2ft/s^2$

So, we have:

$0 = 260.22 - 32.2t$

Collect Like Terms

$32.2t = 260.22$

Make t the subject

$t = \frac{260.22}{ 32.2}$

$t = 8.08s$

The maximum height is then calculated as:

$S_{max} = S_0 + ut + \frac{1}{2}at^2$

This gives:

$S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 32.2 * 8.08^2$

$S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 2102.22$

$S_{max} = 89.6 + 260.22 * 8.08 - 1051.11$

$S_{max} = 1141.0676$

$S_{max} = 1141.07ft$

Hence, the maximum height is 1141.07ft

8 0

3 years ago