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AfilCa [17]
2 years ago
12

What are the available motor sizes for 2023 ariya ac synchronous drive motor systems in kw?.

Engineering
1 answer:
Anika [276]2 years ago
5 0

The available motor sizes for 2023 Ariya AC synchronous drive motor systems are:

40 kW.

62 kW.

160 kW.

<h3>What is a synchronous motor?</h3>

A synchronous motor refers to an alternating current (AC) electric motor in which the rotational speed of the shaft is directly proportional (equal) to the frequency of the supply current, especially at a steady state.

In Engineering, the available motor sizes for 2023 Nissan Ariya AC synchronous drive motor systems include the following:

40 kW.

62 kW.

160 kW.

Read more on synchronous motor here:

brainly.com/question/12975042

#SPJ1

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Kieran and Kurt spend most of their day performing physical labor, aligning materials, and inspecting projects for quality and s
xxMikexx [17]

Answer:

Kieran is a Carpenter, and Kurt is a Drafter

Explanation:

Among all the professions listed, Kurt can only possibly be a Drafter.  A Drafter is an engineering technician who makes detailed technical drawings or plans for machinery, buildings, electronics, infrastructure, sections, etc. Drafters make use of computer software and manual sketches to convert the designs, plans, and layouts of engineers and architects into a set of technical drawings. All the other professions will at some point need for the professional to stand and work at an height above the ground except for a drafter, whose feet will remain on the ground at almost all times.

5 0
3 years ago
Read 2 more answers
thermo A large container ship is propelled by a heat engine that uses fuel oil as a heat source and sea water as a heat sink. Th
TEA [102]

Answer:

\eta = 4.617\times 10^{-4}\,(0.046\,\%), \dot Q_{out} = 162369.444\,kW

Explanation:

The definition of thermal efficiency follows to this expression:

\eta = \frac{\dot W}{\dot Q_{in}}

\eta = \frac{75\,kW}{\left(43000\,\frac{kJ}{L} \right)\cdot \left(13600\,\frac{L}{h} \right)\cdot \left(\frac{1\,h}{3600\,s}  \right)}

\eta = 4.617\times 10^{-4}\,(0.046\,\%)

The rate of heat transfer to the ocean is:

\dot Q_{out} = \dot Q_{in}-\dot W

\dot Q_{out} = \left(43000\,\frac{kJ}{L}  \right)\cdot \left(13600\,\frac{L}{h}  \right)\cdot \left(\frac{1\,h}{3600\,s}  \right)-75\,kW

\dot Q_{out} = 162369.444\,kW

3 0
4 years ago
Select the correct answer.
bonufazy [111]

Answer:

OD.

plate

Explanation:

3 0
3 years ago
Over 30 day period, a lake surface area is 1260 acres. The inflow is 36 cfs, thee outflow is 30 cfs. Seepage loss is 1.5 in. The
Elis [28]

Answer:

  -0.1 inches

Explanation:

The net inflow is ...

  36 cfs -30 cfs = 6 cfs

The number of seconds in 30 days is ...

  (3600 s/h)(24 h/da)(30 da) = 2,592,000 . . . . seconds/(30 days)

Then the volume of inflow is ...

  (6 ft^3/s)(2,592,000 s) = 15,552,000 ft^3

The number of square feet in 1260 acres is ...

  (1260 ac)(43560 ft^/ac) = 54,885,600 ft^2

So, the increase in depth due to the inflow is ...

  (15,552,000 ft^3)/(54,885,600 ft^2) ≈ 0.283353 ft ≈ 3.4002 in

__

The net change in water level is then ...

  inflow - seepage + precipitation - evaporation

  3.4 in -1.5 in +4.0 in -6.0 in = -0.1 in

The water level change in the period is -0.1 inch.

5 0
3 years ago
Please explain what is the difference between engineering stress and true stress in a tensile test?
NNADVOKAT [17]

Answer:

Explanation:

Engineering Stress is defined as Load applied to the original cross-sectional area which we have taken in the start.

True stress is defined as the load divided by area of cross-section of specimen at that instant.

Engineering stress  and true stress can be expressed by relation

\sigma _T=\sigma _E\left ( 1+\epsilon _E\right )

Where

\sigma _T=True\ stress

\sigma _E=Engineering\ stress

\epsilon _E=Engineering\ Strain

6 0
4 years ago
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