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slava [35]
3 years ago
8

Acid mine drainage results from acidic water formed belowground that makes its way to the surface; the acidic water is formed as

a result of the flooding of abandoned mines where the underground watera) reacts with a type of rock, pyrite, which releases iron and hydrogen ionsb) reacts with sulfur dioxide and nitrogen dioxide to form sulfuric and nitric acidsc) flushes out the chemicals used in the mining processd) permeates a limestone layer that lowers the pHe) reacts with copper and aluminum to form pyrite rock and hydrogen ions
Chemistry
1 answer:
Marizza181 [45]3 years ago
6 0

Answer:

El drenaje ácido de la mina resulta del agua ácida formada bajo tierra que llega a la superficie; el agua ácida se forma como resultado de la inundación de minas abandonadas donde el agua subterránea reacciona con un tipo de roca, pirita, que libera iones de hierro e hidrógenob) reacciona con dióxido de azufre y dióxido de nitrógeno para formar ácidos sulfúrico y nítricoc) se descarga los productos químicos utilizados en la minería procesada) impregna una capa de piedra caliza que reduce el pHe) reacciona con cobre y aluminio para formar roca de pirita e iones de hidrógeno

Explanation:

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Aleks04 [339]

To solve the question we will assume that the gas behaves like an ideal gas, that is to say, that there is no interaction between the molecules. Assuming ideal gas we can apply the following equation:

PV=nRT

Where,

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R is a constant

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Now, we have two states, an initial state, and a final state. The conditions for each state will be.

Initial state (1)

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T1=-18°C=255.15K

Final state(2), STP conditions

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We will assume that the number of moles remains constant, so the nR term of the first equation will be constant. For each state, we will have:

\begin{gathered} \frac{P_1V_1}{T_1}=nR \\ \frac{P_2V_2}{T_2}=nR \end{gathered}

Since nR is the same for both states, we can equate the equations and solve for V2:

\begin{gathered} \frac{P_{2}V_{2}}{T_{2}}=\frac{P_1V_1}{T_1} \\ V_2=\frac{P_{1}V_{1}}{T_{1}}\times\frac{T_2}{P_2} \end{gathered}

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8 0
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