1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SOVA2 [1]
3 years ago
8

For the reaction below, Kp = 1.59 at 100°C. If 1.0 g of SrCO3 is placed in an empty 5.00 L reactor and allowed to reach equilibr

ium, what will be the pressure in the reactor?
Chemistry
1 answer:
Sergio [31]3 years ago
8 0

Answer:

p_{CO_2}^{eq}=1.59atm

Explanation:

Hello, in this case, one could consider the undergoing chemical reaction as:

SrCO_3(s)\rightleftharpoons SrO(s)+CO_2(g)

Thus, since 1.0 g of strontium carbonate is placed, the equilibrium equation takes the following form, excluding the solid-stated species and considering just the carbon dioxide as it is gaseous:

Kp=p_{CO_2}^{eq}=1.59atm

Hence, since at the beginning there is no carbon dioxide, its pressure at equilibrium equals Kp:

Kp=p_{CO_2}^{eq}=1.59atm

Which was clearly defined above.

Best regards.

You might be interested in
Please help me
Step2247 [10]
A) Combustion
Hope this helps
8 0
4 years ago
Read 2 more answers
Can someone please help me please dont scroll
Nostrana [21]
Quantitative is anything that is relating to a number value. Think “quantity”

Example:

1. There are 5 ml of water
2. There are 3 beakers
3. It takes 30 minutes for the reaction

Qualitative is about characteristics that can be described

Example

1. The liquid is green
2. The solution turned into a gas
3. Bubbles were produced
4 0
2 years ago
The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular fo
GaryK [48]

Answer:

D)subscript of C in molecular formula = n x subscript of C in empirical formula

Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

.The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular formula and the empirical formula? a)<br /><br /> empirical formula mass / molecular mass = n<br /><br /> B) molecular mass = element mass / empirical formula mass ´ 100<br /><br /> c) subscript of H in empirical formula = 2  subscript of H in molecular formula<br /><br /> D) subscript of C in molecular formula = n  subscript of C in empirical formula<br /><br />

An empirical formula can be regarded as "shorten form" of a molecular formula. Instance of this is

A compounds CH4, C2H8, C4H12... with empirical formula of CH4. In this case a constant "n" represent the difference that exist between empirical formula and molecular formula, "n" which is a whole number, molecular formula is the numerator.

Therefore, subscript of C in molecular formula = n x subscript of C in empirical formula

8 0
3 years ago
Perform the following conversions:
jek_recluse [69]

Answer :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=\frac{5}{9}\times (^oF-32)

The conversion used for the temperature from degree Celsius to Kelvin is:

K=^oC+273

(a) 1.06^oF

^oC=\frac{5}{9}\times (^oF-32)

^oC=\frac{5}{9}\times (1.06^oF-32)

^oC=-17.188

The temperature in degree Celsius is, -17.188^oC

K=^oC+273

K=-17.188+273

K=255.812

The temperature in Kelvin is, 255.812 K

(b) 3410^oC

^oC=\frac{5}{9}\times (^oF-32)

3410^oC=\frac{5}{9}\times (^oF-32)

^oF=6106

The temperature in degree Fahrenheit is, 6106^oF

K=^oC+273

K=3410+273

K=3683

The temperature in Kelvin is, 3683 K

(c) 6.1\times 10^3K

K=^oC+273

6.1\times 10^3K=^oC+273

^oC=5827

The temperature in degree Celsius is, 5827^oC

^oC=\frac{5}{9}\times (^oF-32)

5827^oC=\frac{5}{9}\times (^oF-32)

^oF=10456.6

The temperature in degree Fahrenheit is, 10456.6^oF

8 0
3 years ago
The diagram shows the movement of particles from one end of the container to the opposite end of the container. A cylindrical co
trapecia [35]

Answer:

C. effusion because there is a movement of a gas through a small opening into a larger volume

Explanation:

Effusion makes fluid/gas molecules move to the container with less pressure or larger volume. In diffusion, the movement should work two ways even though one side might receive more. But in effusion, the movement is rather one way.

This case shows how effusion work because its not the concentration that makes the balls moving to the bottom part of the container. No ball moving from bottom container to top either.

3 0
4 years ago
Read 2 more answers
Other questions:
  • Persamaan ion for Mg+HCI
    12·1 answer
  • Which structure is responsible for breaking down sugar molecules in order to supply energy to the cell?
    13·1 answer
  • This is the process where wind, water or ice may add a layer of sediment to a landform.
    8·2 answers
  • What will create static electricity?
    9·2 answers
  • Recently you viewed a movie in which a spaceship blows up outside a space station. The people inside the space station jump with
    7·1 answer
  • A pendulum has 721 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
    15·2 answers
  • Una solución contiene 25.10 ml de H2SO4 (densidad de 1.34 g/ml). Calcular la molaridad, moralidad, normalidad, fracción molar de
    9·1 answer
  • The 2s orbital is at n=2. *<br> True<br> False
    5·2 answers
  • Which form of energy is associated with the random motion of particles in a gas?
    12·2 answers
  • BALANCE THIS EQUATION:<br> C4H10 + O2 = C02 + H20
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!