When carbon undergoes sp2 hybridization it forms methane ? I believe.
Answer:
12120 g + O2 = 15084 g
m Zn = 12.120 Kg
m óxido = 15.084 Kg
1. calcular la masa de cinc en gramos
g = 12,120 Kg x 1000 = 12120 g de cinc
g = 15.084 Kg x 100 = 15084 g de oxígeno
2. calcular gramos de Oxigeno
g O = 15084 g - 12120 g = 2964 g O2
3. calcular % de Zn y O
%m/m ( m soluto / m solc.) x 100
%m/m (Zn) = ( 1210 g / 15084 g ) x 100
% m/m (Zn) = 80.35 % = 80.35 g
%m/m (O) = ( 2964 g / 15084 g ) x 100
% m/m (Zn) = 19.65 % = 19.65 g
4. Calcular moles de cada elemento
Zn: 80.35 g / 65.38 g/mol = 1.228 mol
O: 19.65 g / 16 g/mol = 1.228 mol
5. dividir entre el menor de los elementos
Zn: 1.228 mol / 1.228 mol = 1
O: 1.228 mol / 1.228 mol = 1
6. Fórmula empírica: ZnO
The law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as system's mass cannot change, so quantity cannot be added nor removed. Hence, the quantity of mass is conserved over time.
The law implies that mass can neither be created nor destroyed, although it may be rearranged in space, or the entities associated with it may be changed in form. For example, in chemical reactions, the mass of the chemical components before the reaction is equal to the mass of the components after the reaction. Thus, during any chemical reaction and low-energy thermodynamic processes in an isolated system, the total mass of the reactants, or starting materials, must be equal to the mass of the products.
According to the Law of Conservation, all atoms of the reactant(s) must equal the atoms of the product(s).
As a result, we need to balance chemical equations. We do this by adding in coefficients to the reactants and/or products. The compound(s) itself/themselves DOES NOT CHANGE.
Concentration is the number of moles of solute in a fixed volume of solution
Concentration(c) = number of moles of solute(n) / volume of solution (v)
25.0 mL of water is added to 125 mL of a 0.150 M LiOH solution and solution becomes more diluted.
original solution molarity - 0.150 M
number of moles of LiOH in 1 L - 0.150 mol
number of LiOH moles in 0.125 L - 0.150 mol/ L x 0.125 L = 0.01875 mol
when 25.0 mL is added the number of moles of LiOH will remain constant but volume of the solution increases
new volume - 125 mL + 25 mL = 150 mL
therefore new molarity is
c = 0.01875 mol / 0.150 L = 0.125 M
answer is 0.125 M
Answer:
The excited state electron configuration of an atom indicates the promotion of a valence electron to a higher energy state.
