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Dafna1 [17]
3 years ago
5

When a glass rod is rubbed with silk, it becomes positive and the silk becomes negative—yet both attract dust. Does the dust hav

e a third type of charge that is attracted to both positive and negative? Explain. g
Physics
1 answer:
lina2011 [118]3 years ago
6 0

Answer:

The dust does have any third charge.

Explanation:

                In the context, the glass rod gets positively charged and so it induces a negative charge on the dust particles which are neutral. Thus the face of the dust particle which is near to the rod becomes negative charge and the opposite face of the dust gets equal positive charge and hence it ensures the neutrality of the dust particle but still being attracted to the glass rod.

               And in the case of the negatively charged silk, the silk induces or gives positive charge to the dust particle which is neutral in charge. The face which is near to the silk gets positive charge and the other face becomes negative charge, again ensuring its neutrality and being attracted to the glass rod.

               This shows how both positive charged rod and negatively charged silk attracts the neutral dust particle.

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S ship maneuvers to within 2.50x10^3 m of an islands 1.80x10^3 m high mountain peak and fires a projectile at an enemy ship 6.10
lilavasa [31]

velocity of the projectile is given as

v = 2.50 \times 10^3 m/s

now the angle is given as 75 degree

so here we will have

v_x = 2.50 \times 10^3 cos75 = 0.65 \times 10^3 m/s

v_y = 2.50 \times 10^3 sin75 = 2.4 \times 10^3 m/s

now the time taken to reach the peak is given as

t = \frac{x}{v_x}

t = \frac{2.50 \times 10^3}{0.65 \times 10^3} = 3.86 s

now the height moved by the projectile in same time is given as

y = v_y t + \frac{1}{2}at^2

now we have

y = (2.4 \times 10^3)(3.86) - \frac{1}{2}(9.81)(3.86)^2

y = 9.2 \times 10^3 m

so distance between the peak and projectile is given as

d = 9.2 \times 10^3 - 1.80 \times 10^3 = 7.4 \times 10^3 m

5 0
3 years ago
A 1500 kg car, initially traveling at 22.0 m/s, hits its brakes and skids to a stop. Determine the work done by friction.
Sedbober [7]

Answer:

<em>The work done by the car is 363 kJ</em>

Explanation:

Work : Work is said to be done when a Force moves an object through a certain distance. Work and Energy are interchangeable because they have the same unit. The unit of work is Joules (J).

Mathematically work done can be expressed as,

E = W = 1/2mv²

W =  1/2mv²................................ Equation 1

Where E = Energy, W = work done, m = mass of the car, v = velocity of the car

<em>Given: m=1500 kg, v=22 m/s</em>

<em>Substituting these values into equation 1</em>

<em>W = 1/2(1500)(22)²</em>

<em>W = 750 × 484</em>

<em>W = 363000 J</em>

<em>W = 363 kJ</em>

<em>Thus the work done by the car is 363 kJ</em>

8 0
3 years ago
A child walks due east on the deck of a ship at 2 miles per hour. the ship is moving north at a speed of 18 miles per hour. find
garik1379 [7]
Refer to the figure shown below.

The velocity of the child and the velocity of the ship should be added vectorially to find the speed and direction of the child relative to the water surface.

The magnitude of the child's velocity is
v = √(2² + 18²) = 18.11 mph

The direction of the child's speed is
θ = tan⁻¹ (18/2) = tan⁻¹ 9 = 83.7° north of east or counterclockwise from the eastern direction.

Answer:
The magnitude is 18.1 mph.
The direction is 84° north of east.

8 0
3 years ago
A What quantity is equal to​
natulia [17]

Answer:

Option B is correct

Explanation:

acceleration is equal to rate of change of velocity.

6 0
3 years ago
Which gas law states that the pressure of a gas decreases when volume is increased and the temperature is unchanged?
Makovka662 [10]
<span>Boyle's Law, in short, states that the volume of a gas is inversely proportional to its pressure AS LONG AS THE TEMPERATURE REMAINS UNCHAnged </span>
6 0
4 years ago
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