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Zinaida [17]
3 years ago
11

5 questions

Mathematics
1 answer:
zzz [600]3 years ago
4 0

This is a comment---

Are you acually in middle school because this is algebra 2 and im learning this now in High school

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In August 2003, 56% of employed adults in the United States reported that basic mathematical skills were critical or very import
Serga [27]

Answer:

Yes

Step-by-step explanation:

First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.

It has mean μ= np =  30×0.56=16.8

standard deviation s = √npq

sqrt(30×0.56×(1-0.56)) = 2.71

So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.

7 0
3 years ago
Help please first person to answer it right gets Brainliest
mihalych1998 [28]

Answer:

its the first one

Step-by-step explanation:

3 0
3 years ago
Use the properties of rational exponents to simplify 6/6 1/4
Alexeev081 [22]

Answer:

one

Step-by-step explanation:

Use the properties of rational exponents

6 0
3 years ago
Carl ran around the track 3 more times than Daria and 2 fewer times than Erin. When they were done they added up the number of l
Paul [167]

Answer:

Total laps = 10d

Step-by-step explanation:

Let c = Carl's laps

d = Daria's laps

e = Erin's laps

c = 3d

c = e/2

c + d + e = totals laps

We can insert 3d in place of c in the third equation

3d + d + e = total laps

Also, e/2 equals 3d

e/2 = 3d

Multiply both sides by 2

(e/2 = 3d)2

e = 6d

Insert the new e

3d + d + 6d = 10d = totals laps

3 0
2 years ago
Find the second derivative, do not have to simplify
zlopas [31]

f(x)=\sec(\pi x)=\dfrac{1}{\cos(\pi x)}=[\cos(\pi x)]^{-1}\\\\\text{use}\\\\(a^n)'=na^{n-1}\\\\(\cos x)'=-\sin x\\\\f'(g(x))=f'(g(x))\cdot g'(x)

f'(x)=\left\{[\cos(\pi x)]^{-1}\right\}'=-[\cos(\pi x)]^{-2}\cdot[-\sin(\pi x)]\cdot\pi\\\\=\dfrac{\pi\sin(\pi x)}{[\cos(\pi x)]^2}=\pi\dfrac{\sin(\pi x)}{\cos(\pi x)}\cdot\dfrac{1}{\cos(\pi x)}\\\\=\pi\tan(\pi x)\sec(\pi x)

6 0
3 years ago
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