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3 years ago

Why does magnesium react most vigorously with hydrochloric acid?

Chemistry

1 answer:

Anna007 [38]3 years ago

4 0

Answer:

The magnesium reacts with the acid, producing visible bubbles of hydrogen gas.

Explanation:

Optional) If the flame of a butane fireplace lighter is held above the bursting bubbles, they will produce audible pops as the hydrogen ignites. Magnesium ribbon is a flammable solid. Hydrochloric acid is a corrosive liquid. Hope this helps :).

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What happens to the mass when a substance changes states

Norma-Jean [14]

If the the level of water in a container is compared before and after the fusion, it can be realized that the ice has a higher level than that of liquid water: solid and liquid water does not have the same volume.
We can generalize:
A state change always causes a change in volume.
Comment:
Water is an exception, volume increases during a melting for most of substances.

8 0

3 years ago

Which describes the role of carbon dioxide in photosynthesis?

jeka57 [31]

Answer:

It is a reactant, so it enters the plant.

Explanation:

Hello,

Photosynthesis is the natural process occurring when plants produce sugar and oxygen by using the visible light as the catalyst to undergo the following chemical reaction:

$6CO_2+6H_2O-->C_6H_{12}O_6+6O_2$

In such a way, it is seen that the carbon dioxide has the role of reactant as it is used by the plant, that is, it enters the plant to allow the photosynthesis to be carried out.

Best regards.

6 0

3 years ago

Read 2 more answers

Water freezes at _____. A. 273°C B. -273°C C. 273 K D. -273 K

BartSMP [9]

Correct answer is A

6 0

3 years ago

How to do limiting reagents for chemistry?

gavmur [86]

Balance the chemical equation for the chemical reaction.
Convert the given information into moles.
Use stoichiometry for each individual reactant to find the mass of product produced.
The reactant that produces a lesser amount of product is the limiting reagent.
The reactant that produces a larger amount of product is the excess reagent.
To find the amount of remaining excess reactant, subtract the mass of excess reagent consumed from the total mass of excess reagent given.

4 0

3 years ago

2. A solution is made by adding 1.23 mol of KCl to 1000.0 g of water. Assume that the

ladessa [460]

Answer:

a. 74.55 g/mol.

b. 91.70 g.

c. 8.40%.

d. 1.23 mol/L.

Explanation:

a. Calculate the formula weight of KCl.

∵ Formula weight of KCl = atomic weight of K + atomic weight of Cl

atomic weight of K = 39.098 g/mol, atomic weight of Cl = 35.45 g/mol.

∴ Formula weight of KCl = atomic weight of K + atomic weight of Cl = 39.098 g/mol + 35.45 g/mol = 74.548 g/mol ≅ 74.55 g/mol.

b. Calculate the mass of KCl in grams.

we can use the relation:

no. of moles (n) = mass/molar mass.

∴ mass of KCl = n*molar mass = (1.23 mol)*(74.55 g/mol) = 91.69 g ≅ 91.70 g.

c. Calculate the percent by mass of KCl in this solution.

The mass % of KCl = (mass of KCl/mass of the solution) * 100.

mass of KCl = 91.70 g,

mass of the solution = 1000.0 g of water + 91.70 g of KCl = 1091.70 g.

∴ The mass % of KCl = (91.70 g/1091.70 g)*100 = 8.399% ≅ 8.40%.

d. Calculate the molarity of the solution.

Molarity is the no. of moles of solute per 1.0 L of the solution.

M = (no. of moles of KCl)/(Volume of the solution (L))

no. of moles of KCl = 1.23 mol,

Volume of the solution = mass of water / density of water = (1000.0 g)/(1.00 g/mL) = 1000.0 mL = 1.0 L.

M = (1.23 mol)/(1.0 L) = 1.23 mol/L.

3 0

4 years ago