Answer:
The heat of vaporisation of methanol is "3.48 KJ/Mol"
Explanation:
The amount of heat energy required to convert or transform 1 gram of liquid to vapour is called heat of vaporisation
When 8.7 KJ of heat energy is required to vaporize 2.5 mol of liquid methanol.
Hence, for 1 mol of liquid methanol, amount of heat energy required to evaporate the methanol is = 
= 3.48 KJ
So, the heat of vaporization 
Therefore, the heat of vaporization of methanol is 3.48KJ/Mol
Answer:<em> A transfer of electrons occurs when fluorine and calcium react to form an ionic compound. This is because calcium is in group two and so forms ions with a two positive charge. ... A pairs of shared electrons makes one covalent bond. The compound formed is known as a molecule***</em>
Answer:
0.1066 hours
Explanation:
A common pesticide degrades in a first-order process with a rate constant (k) of 6.5 1/hours. We can calculate its half-life (t1/2), that is, the times that it takes for its concentration to be halved, using the following expression.
t1/2 = ln2/k
t1/2 = ln2/6.5 h⁻¹
t1/2 = 0.1066 h
The half-life of the pesticide is 0.1066 hours.
Answer:
Gold is a metal, more specifically a transition metal, whereas Oxygen is a nonmetal, more specifically a reactive nonmetal. Using this information, you can compare and contrast metals, nonmetals, and metalloids.
Metals are:
Shiny
High melting point
Mostly silver or gray in color
Mostly solids at room temperature – Mercury (Hg) is a liquid at room temperature
Malleable – able to be hammered into a thin sheet
Ductile – able to be drawn/pulled into a wire
Good conductors of heat and electricity
Nonmetals are:
Dull
Low melting point
Brittle – break easily
Not malleable
Not ductile
Poor conductors of heat and electricity
Metalloids are:
Found on the “zig-zag” line on the Periodic Table of Elements
Have properties of both metals and nonmetals
Can be shiny or dull
Semiconductors – able to conduct electricity under certain conditions
Explanation:
Reccomend this site for questions llike these: https://ptable.com/#Properties
Using the answer from the first part, we know that 2.957 moles of bismuth have formed. Moreover, the molar ratio between bismuth and carbon monoxide is:
2 : 3
Using the method of ratios,
2 : 3
2.957 : CO
CO = (3 * 2.957) / 2
CO = 4.4355
4.436 moles of carbon monoxide will be formed
