Answer:
grams KI needed = 31.9 grams
Explanation:
? g KI + 500 g water => 6.0% KI solution
let x = grams KI needed.
Percent = part/total x 100% = (x/x+500)·100% = 6.0%
Solve for 'x' ...
x / x + 500 = 6/100 = 0.06 => x = 0.06(x + 500) => x = 0.06x + 30
x - 0.06x = 30 => 0.94x = 30 => x = 30/0.94 = 31.9 gms KI needed.
I think the correct answer is c if not it’s d
Answer is: <span>the molecular formula for a glucose polymer is C</span>₆₀H₁₀₂O₅₁.<span>
For every link one molecule of water is released, so if we have ten molecules of glucose, there is nine links and nine molecules of water (H</span>₂O)<span> are released.
molecular formula = 10</span>·<span>C</span>₆H₁₂O₆ - 9·H₂O.
<span>carbon atoms = 10 </span>· 6 = 60.
<span>hydrogen atoms = 10 </span>· 12 - 9 · 2 = 102.
<span>oxygen atoms = 10 </span>· 6 - <span>9 </span>· 1 = 51.<span>
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