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2 years ago

The Connecticut Bueller theory assumes that particles of an ideal gas are

Chemistry

1 answer:

postnew [5]2 years ago

3 0

<span>are in random, constant, straight-line motion</span>

<span>your welcome :)</span>

<span>all I Ask is for a thank u peaceeee</span>

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Define solubility. the amount of a substance that will dissolve in a given amount of solvent a solid mixed with another solid a

slavikrds [6]

Answer:

You answered your own question

5 0

2 years ago

Arunner sprints 550 feet in 100 seconds. If the runner can hold this pace for an hour

Alex

<h3>Answer:</h3>

Distance traveled is 9.055 km

<h3>Explanation:</h3>

Speed is given by dividing distance by time.

The distance given is 550 ft and the time is 100 seconds.

Therefore; Speed = 550 ft ÷ 100 sec

= 5.5 ft/sec

We can calculate the distance the runner covered in one and half hour.

Time = 1.5 hours

But 1 hour = 3600 sec

1.5 hours = (1.5 × 3600)

= 5400 sec

Distance is given by multiplying speed and time

Thus; Distance = 5.5 ft/sec × 5400 sec

= 29700 ft

But; 1 m = 3.28 ft

1000 m = 1 km

Therefore; 29700 ft will be equivalent to

= 29700 ft/3.28 ft

= 9054.878 M

but 1000 m = 1 km

Thus, distance = 9054.878 ÷ 1000 m

= 9.055 km

6 0

2 years ago

How does carbon-14 differ from the other carbon atoms

just olya [345]

Answer:

Carbon-14 is an isotope of carbon and differs in the number of neutrons in their nucleus.

Explanation:

all isotopes have the same number of protons and electrons, but differ in the number of neutrons. They have identical chemical behaviour but with different atomic masses and physical properties

4 0

3 years ago

In a gas grill, 29 lbs propane C3H8 are

dimulka [17.4K]

Answer : The mass of combustion products formed are 134 lbs.

Explanation :

The balanced chemical reaction will be:

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

Given :

Mass of $C_3H_8$ = 29 lbs = 13154.2 g

conversion used : 1 lbs = 453.592 g

Molar mass of $C_3H_8$ = 44 g/mole

First we have to calculate the moles of $C_3H_8$ .

$\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{13154.2g}{44g/mole}=298.9moles$

Now we have to calculate the moles of $CO_2$ and $H_2O$ .

From the balanced chemical reaction we conclude that,

As, 1 mole of $C_3H_8$ react to give 3 moles of $CO_2$

So, 298.9 mole of $C_3H_8$ react to give $298.9\times 3=896.7$ moles of $CO_2$

and,

As, 1 mole of $C_3H_8$ react to give 4 moles of $H_2O$

So, 298.9 mole of $C_3H_8$ react to give $298.9\times 4=1195.6$ moles of $H_2O$

Now we have to calculate the mass of $CO_2$ and $H_2O$ .

Molar mass of $CO_2$ = 44 g/mole

Molar mass of $H_2O$ = 18 g/mole

$\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass }CO_2$

$\text{Mass of }CO_2=896.7mole\times 44g/mole=39454.8g=86.98lbs$

and,

$\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass }H_2O$

$\text{Mass of }H_2O=1195.6mole\times 18g/mole=21520.8g=47.44lbs$

The total mass of products = Mass of $CO_2$ + Mass of $H_2O$

The total mass of products = 86.98 + 47.44 = 134.42 ≈ 134 lbs

Therefore, the mass of combustion products formed are 134 lbs.

6 0

2 years ago

Calculate the molarity of glucose in a solution that which contains 35 g of glucose in 0.16 kg of phenol

sleet_krkn [62]

C(Molarity) = n of solute/V of solution (mol/L)

glucose(C6H12O6) = 180g/mol
glucose 35g = 35g/(180g/mol) = 0.1944mol

We need density of solution here, and I assume it as density of phenol, 1.07g/mL. (I don't know why the question doesn't contain it)

phenol 0.16kg = 0.16kg/(1.07kg/L) = 0.1495L

0.1944mol/0.1495L = 1.300M(mol/L)

5 0

3 years ago