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2 years ago

How are carbon-based molecules suited for sustaining life?

Chemistry

1 answer:

IrinaVladis [17]2 years ago

8 0

$\huge\fcolorbox{red}{pink}{Answer ♥}$

Life on Earth is based on carbon, likely because each carbon atom can form bonds with up to four other atoms simultaneously. This quality makes carbon well-suited to form the long chains of molecules that serve as the basis for life as we know it, such as proteins and DNA.

Hope it helps uh ✌️✌️✌️

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Answering questions by analyzing specific observations and using them to come to a more general understanding is known as ______

ad-work [718]

The correct answer would be inductive reasoning.

Primavera?

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2 years ago

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What should you do if you need to determine the odor of a chemical or a solution?

Cerrena [4.2K]

Answer:

Explanation:

When you are in the laboratory and take a direct sniff of the chemicals you are using, you run the risk of damaging your mucous membranes or your lungs. When it is necessary to smell chemicals in the lab, the proper technique is to cup your hand above the container and waft the air toward your face.

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2 years ago

Assuming it behaves as an ideal gas, calculate the density of sulfur dioxide, so2, at stp.

Arisa [49]

Hello!

At Standard Pressure and Temperature, an ideal gas has a molar density of 0,04464 mol/L.

So, we need to apply a simple conversion factor to calculate the density of Sulfur Dioxide using the molar mass of Sulfur Dioxide.

$\frac{0,04464 mol SO_2}{1 L SO_2}* \frac{64,066 g SO_2}{1 mol SO_2}=2,8599 g/L$

So, the Density of Sulfur Dioxide (SO₂) at STP is 2,8599 g/L

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2 years ago

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HEY I NEED ALL ANSWERS RIGHT NOW IT'S MISSING AND MY TEACHER ARE GRADING THEM NOW YOU WILL BE MARKED BRAINIEST

emmainna [20.7K]

Molar mass of butane:-

4(12)+10=58u

Moles of Butane:-

100/58=1.7mol

#16

2mols of Butane produce 8mol CO_2
1mol of butane produces 4mol CO_2

Moles of CO_2

4(1.7)=6.8mol

Mass of CO_2:-

44(6.8)=299.2g

#17

2mols of butane need 13mol O_2
1mol of butane needs 6.5mol O_2

Moles of O_2

6.5(1.7)=11.05mol

Mass of O_2

11.05(32)=353.6g

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2 years ago

A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If

NemiM [27]

Answer:

<h3>25.0 grams is the mass of the steel bar.</h3>

Explanation:

Heat gained by steel bar will be equal to heat lost by the water

$Q_1=-Q_2$

Mass of steel= $m_1$

Specific heat capacity of steel = $c_1=0.452 J/g^oC$

Initial temperature of the steel = $T_1=2.00^oC$

Final temperature of the steel = $T_2=T=21.50^oC$

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2= 105 g$

Specific heat capacity of water= $c_2=4.18 J/g^oC$

Initial temperature of the water = $T_3=22.00^oC$

Final temperature of water = $T_2=T=21.50^oC$

$Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))$

On substituting all values:

$(m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}$

<h3>25.0 grams is the mass of the steel bar.</h3>

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3 years ago

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