Let's handle this case by case.
Clearly, there's no way both children can be girls. There are then two cases:
Case 1: Two boys. In this case, we have 13 possibilities: the first is born on a Tuesday and the second is not (that's 6 possibilities, six ways to choose the day for the second boy), the first is not born on a Tuesday and the second is (6 more possibilities, same logic), and both are born on a Tuesday (1 final possibility), for a total of 13 possibilities with this case.
Case 2: A boy and a girl. In this case, there are 14 possibilities: The first is a boy born on a Tuesday and the second is a girl born on any day (7 possibilities, again choosing the day of the week. We are counting possibilities by days of the week, so we must be consistent here.), or the first is a girl born any day and the second is a boy born on a Tuesday (7 possibilities).
We're trying to find the probability of case 1 occurring given that case 1 or case 2 occurs. As there's 13+14=27 ways for either case to occur, we have a 13/27 probability that case 1 is the one that occurred.
Answer:
Step-by-step explanation:
The justification of each given statements in the question are:
11) F. Definition of right angle.
12) D. Definition of supplementary <'s.
13) A. Definition of congruence.
14) C. Definition of complementary <'s.
15) L. Congruent supplementary theorem
16) H. Vertical angle theorem.
17) G. Angle addition postulate.
18) J. Supplementary theorem.
Answer:
Option C. 
Step-by-step explanation:
we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the sample space is the total number of possible outcomes
The event space is the number of outcomes in the event you are interested in.
so
Let
x------> size of the event space (total person's hemoglobin level of 9 or above with age above 35 years)
y-----> size of the sample space (total person's age above 35 years)
so
In this problem we have
Complete the table to find the total person's hemoglobin level of 9 or above (person's age above 35)
Let
y------> total person's hemoglobin level between 9 and 11 (person's age above 35)
Find the value of x
substitute the values
Answer:
Correct option is
C
36.25
Modal class =30−40
So we have, l=30,f0=12,f1=32,f2=20 and h=10
⇒ Mode=l+2f1−f0f2f1−f0×h
=30+2×32−12−2032−12×10
=30+6.25
=36.25
∴ Mode =36.25
-2x + xy = 30.....when y = 8
-2x + 8x = 30
6x = 30
x = 30/6
x = 5 <==
