From the balanced equation, we can see that 1 mole of CH4
releases 802.3 kJ of heat upon combustion. The mass of 1 mole of CH4 is:
mass CH4 = 16.04 grams
So by ratio and proportion:
mass required = (-268 kJ) / (-802.3 kJ / 16.04 grams)
<span>mass required = 0.334 grams</span>
Pretty sure the answer is true
Answer: The %v/v of the given KCl solution is 7.6%.
Explanation:
Given: Volume of solute =
Volume of solution =
Formula used to calculate %v/v is as follows.
Substitute the values into above formula as follows.
Thus. we can conclude that the %v/v of the given KCl solution is 7.6%.
Liquid because it can move around with ease.