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sergiy2304 [10]

2 years ago

9

What is the equation of the line described below written in slope-intercept form?

2 answers:

Bond [772]2 years ago

7 0

The line it is parallel to is x + y = 10, but you can put that into slope-intercept form by subtracting x and get y = 10 - x. This is all the working you need to do because the only answer given that has a negative slope is C. y = -x + 4, and parallel lines always have the same slope, so your answer is C. I hope this helps!

solmaris [256]2 years ago

5 0

Answer:

y = -x + 4

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

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F(x)= 3x - 4x2 +6x and g(x)= 5x +2x2 – 3x. What is f(x) g(x)?

goldenfox [79]

f(x)g(x) = 9x² + 10x - 16

<u>Step-by-step explanation:</u>

Step 1:

Given f(x) = 3x - 4 × 2 + 6x and g(x) = 5x + 2 × 2 - 3x

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2 years ago

Line j has an equation of y - 8 = -2/3(x+5). Line K is perpendicular to line j and passes + through (-6, -2). What is the equati

riadik2000 [5.3K]

Answer:

y = $\frac{3}{2}$ x + 7

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

y - 8 = - $\frac{2}{3}$ (x + 5) ← is in point- slope form

with m = - $\frac{2}{3}$

given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{2}{3} }$ = $\frac{3}{2}$

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept ) , then

y = $\frac{3}{2}$ x + c ← is the partial equation

to find c substitute (- 6, - 2 ) into the partial equation

- 2 = - 9 + c ⇒ c = - 2 + 9 = 7

y = $\frac{3}{2}$ x + 7 ← equation of line K

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2 years ago