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Sonja [21]
3 years ago
11

What color bends the most

Physics
2 answers:
castortr0y [4]3 years ago
7 0
The answer you are looking for is violet.
AlexFokin [52]3 years ago
3 0
The correct answer is violet and red.
You might be interested in
Problems related to radiation. (a) The temperature of the Sun’s photosphere is 5700 K. Assume it is a blackbody. What is the pea
sineoko [7]

Answer:

a) λ = 5,084 10⁻⁷ m , b)  P = 3.63 10²⁶ W , c)  P = 5.8 10²⁷ W and d)  λ = 2.54 10⁻⁷ m

Explanation:

a) The maximum emission of the sun can be calculated using the Win equation

     λ T = 2,898 10⁻³ m.K

     λ = 2,898 10⁻³ / T

     λ = 2,898 10⁻³ / 5700

     λ = 5,084 10⁻⁷ m

     λ = 5,084 10⁻⁷ m (1 10⁹ nm / 1m) =

     λ = 5,084 10² nm = 508.4 nm

      photon in the visible range

b) The emission of the Sun, is described by the Stefan equation

     P = σ A e T⁴

Where σ is the Stefan-Boltzmann constant that vslue is  5,670 10-8 W/m²K⁴, A area of ​​the Sun, and e the emissivity that for a perfect black body is 1

In order to use this equation, we must calculate the area of ​​the sun, we consider it a perfect sphere

      r = 695,000 km (1000m / 1 km) = 6.95 10⁸ m

Area of ​​a sphere

     A = 4π R²

     A = 4π (6.95 10⁸8)²

     A = 6.07 10¹⁸ m²

     P = 5,670 10⁻⁸ 6.07 10¹⁸  1  5700⁴

     P = 3.63 10²⁶ W

c) The new temperature is double the previous one

    T = 2 To

Let's substitute in the formula and calculate

     P = σ A e (2To)⁴

     P = σ A e T⁴ 2⁴

     Po = σ A e T4 = 3.63 10 26 W

   

    P = 16 Po

    P= 16 (3.63 10²⁶)

    P = 5.8 10²⁷ W

d) Let's calculate the explicit value of the temperature and use the Win equation

    T = 2 5700

    T = 11400K

    λ = 2,898 10⁻³ / 11400

    λ = 2.54 10⁻⁷ m

    λ = 2.54 10²nm = 254 nm

photon in the UV range

5 0
3 years ago
What is the magnitude of a point charge in coulombs whose electric field 58 cm away has the magnitude 2.8 N/C?
Yuliya22 [10]

Answer:

q = 1.05 × 10^-10 C

Explanation:

E = 2.8 N/C

r = 58cm = 0.58m

k = 9×10^9

q = ?

E = f/q

E = kq/r²

q = E*r²/k

q = (2.8×0.58²)÷9×10^9

q = 1.05 × 10^-10 C

8 0
3 years ago
Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d
Mumz [18]

Answer:

Part a)

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

Part b)

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

Part c)

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

Explanation:

Red car

mass = 1000 kg

speed = 10 m/s

Yellow car

mass = 2000 kg

speed = 5 m/s

Blue car

mass = 500 kg

speed = 20 m/s

Light Blue car

mass = 1000 kg

speed = 20 m/s

Green car

mass = 500 kg

speed = 10 m/s

Purple car

mass = 4000 kg

speed = 5 m/s

Part a)

Now we know that momentum of each car is product of mass and velocity

so we will have

Red Car

P_1 = m v

P_1 = (1000)(10)

P_1 = 10^4 kg m/s

Yellow Car

P_2 = m v

P_2 = (2000)(5)

P_2 = 10^4 kg m/s

Blue Car

P_3 = m v

P_3 = (500)(20)

P_3 = 10^4 kg m/s

Light Blue Car

P_4 = m v

P_4 = (1000)(20)

P_4 = 2\times 10^4 kg m/s

Green Car

P_5 = m v

P_5 = (500)(10)

P_5 = 5 \times 10^3 kg m/s

Purple Car

P_6 = m v

P_6 = (4000)(5)

P_6 = 2\times 10^4 kg m/s

So the momentum is given as

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

Part b)

Impulse is given as change in momentum so here we can say that final momentum of all the cars will be zero as they all stops and hence the impulse is same as initial momentum of the car

so the order of impulse from largest to least is given as

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

Part c)

Force is defined as rate of change in momentum

Now let say all cars will stop in same time interval

so we will have

Force = \frac{impulse}{time}

so we will have

force is in same order as that of impulse

so it is given as

Purple car = Light Blue car  > (Red car = Yellow Car = Blue car) > Green Car

5 0
4 years ago
Read 2 more answers
Whenever a musician plays a guitar, they pluck one of the guitar strings to produce a standing wave in the string. Then pinch do
UkoKoshka [18]

Answer:

It's due to the distance from either ends of strings origin...

Explanation:

As we know that waves behave moving in a flow from one side to another side and this gives a prospective of motion. Suppose a wave is pinched from the near one end of a guitar then due to the distortion created by the point of tie of strings the wave super imposes and moves with a velocity v and produces a wave frequency f. as we the pinching go down to the center the wave stabilizes itself to a stationary origin right at the center and the frequency then changes accordingly as moving down on the string.

7 0
3 years ago
What is shown in the diagram? A). A turbine B). An electromagnet C). A motor D). A generator
AlexFokin [52]

Answer:

I just answered a question like this. It should be B. An electromagnet :)

Explanation:

4 0
3 years ago
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