Answer:
It will take both pumps 3.08 hours to fill the tank working together.
Explanation:
Pump A can fill the tank in 5 hours. Assuming that the pump gives out a steady flow of water, in one hour, pump A can fill 1/5th of the tank. Similarly, pump B in an hour, fills up 1/8th of the tank.
We must add up these two values, in order to find how much of the tank the two pumps can fill up together in one hour.
1/5 +1/8 =13/40
So 13/40 of the tank is filled in an hour. We need to find how many hours it will take for the entire tank to be filled. To do so, divide 40 by 13. This gives:
3.08 hours to fill up the tank.
Answer:
P= 168258.30696 Pa
Explanation:
Given that
Mass of water vapor m = 19.00 g
Volume of water vapor V = 2.00 L
Temperature of water vapor is T = 111°C
= 384K
Molar mass of water is M = 18.0148 g/mol
Number of moles are
n = m/M
= (1.90 g)/(18.0148 g/mol)
= 0.1054 mol
Pressure inside the container is
P= nRT/V
P= 168258.30696 Pa
Answer:
The change in internal energy of the gas is 578 J
Explanation:
∆U = Q - W
Q = 128 J
W = P(V2 - V1)
P = 1 atm = 101325 N/m^2
V2 = 1.21 L = 1.21/1000 = 1.21×10^-3 m^3
V1 = 5.65 L = 5.65/1000 = 5.65×10^-3 m^3
W = 101325(1.21×10^-3 - 5.65×10^-3) = 101325 × -4.44×10^-3 = -449.883J
∆U = 128 - (-449.883) = 128 + 449.883 = 577.883 = 578 J (to 3 significant figures)