An airplane has mass of 5,320 kg. At takeoff, how much lift force is necessary to accelerate the plane upward at a rate of 1.40m
1 answer:
Answer:
<u>59637.2 N</u> force is required to lift the plane upward.
Explanation:
Mass of the aeroplane (m) = 5320 kg
Acceleration of the plane upward at a rate (a) = 1.40 m/s
"Newton's second law of motion", F - R = ma, where, "force" (F) acting on an object, (R) "resistive force", "mass" (m) of an object and "acceleration" (a).
Force = Resistive force + (mass × acceleration)
Resistive force = mass of an object × acceleration due to gravity. ( we know that acceleration due to gravity is
Resistive force = 5320 × 9.81
Resistive force = 52189.2 N
Force = 52189.2 + (5320kg × 1.40 m/s)
Force = 59637.2 N
At takeoff, <u>59637.2 N</u> force is necessary to accelerate the plane upward at a rate of 1.40 m/s .
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Answer:
gravitational force
electrostatic force
Explanation:
The forces that balloons may exert on each other can be gravitational pull due to the mass of the balloon membrane and the mass of the gas contained in each. This force is inversely proportional to the square of the radial distance between their center of masses.
The Mutual force of gravitational pull that they exert on each other can be given as:
where:
gravitational constant
are the masses of individual balloons
the radial distance between the center of masses of the balloons.
But when there are charges on the balloons, the electrostatic force comes into act which is governed by Coulomb's law.
Given as:
where:
are the charges on the individual balloons
R = radial distance between the charges.