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timofeeve [1]
3 years ago
7

An airplane has mass of 5,320 kg. At takeoff, how much lift force is necessary to accelerate the plane upward at a rate of 1.40m

/ to the second power?
Physics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

Answer:

<u>59637.2 N</u> force is required to lift the plane upward.

Explanation:

Mass of the aeroplane (m) = 5320 kg

Acceleration of the plane upward at a rate (a) = 1.40 m/s

"Newton's second law of motion", F - R = ma, where, "force" (F) acting on an object, (R) "resistive force", "mass" (m) of an object and "acceleration" (a).

Force = Resistive force + (mass × acceleration)

Resistive force = mass of an object × acceleration due to gravity. ( we know that acceleration due to gravity is \left.9.8 \mathrm{m} / \mathrm{s}^{2}\right)

Resistive force = 5320 × 9.81

Resistive force = 52189.2 N

Force = 52189.2 + (5320kg × 1.40 m/s)

Force = 59637.2 N

At takeoff, <u>59637.2 N</u> force is necessary to accelerate the plane upward at a rate of 1.40 m/s .

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5. An acrobat, starting from rest, swings freely on a trapeze of
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The energy conservation and trigonometry we can find the results for the questions about the movement of the acrobat are;

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Let's use trigonometry to find the height, see attached.

         h = L - L cos θ

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They indicate that the initial angle is tea = 48º and the length is L = 3.7 m, let's calculate.

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In conclusion using the conservation of energy and trigonometry we can find the results for the questions about the movement of the acrobat are;

     a) The maximum speed is v = 4.89 m / s

     b) The maximum height is h = 1.22 m

Learn more here: brainly.com/question/13010190

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