Answer:
7A−(I + A)³
=7A−(1³ + A³ +3.I.A² +3.1².A)
=7A−(I+ A².A+3A² +34)
= 7A-(I+A.A+3A+34) (*: A² = A)
=7A-(I+ A² +6A)
= 7A-(I+A+64)
=7A-(1+7A)
=7A-I-7A
=-1
Answer:
The length of the edge of the cube = 4 inches
Step-by-step explanation:
* Lets describe the cube
- It has 6 faces all of them are squares
- It has 8 vertices
- It has 12 equal edges
∵ The volume of any formal solid = area of the base × height
∵ The base of the cube is a square
∴ Area base = L × L = L² ⇒ L is the length of the edge of it
∵ All edges are equal in length
∴ Its height = L
∴ The volume of the cube = L² × L = L³
* Now we have the volume and we want to find the
length of the edges
∵ Its volume = 64 inches³
∴ 64 = L³
* Take cube root to the both sides
∴ ∛64 = ∛(L³)
∴ L = 4 inches
* The length of the edge of the cube = 4 inches
Let his normal weight = 100%
He is 10% more so he is 110%
Divide his weight now by 110% to find his normal weight.
88/1.1 = 80
His normal weight is 80 kg
Angles c and e are vertical
Answer:
angle 4 and angle 8 are congruent
