1 mole of nitric acid produce 1 mole of ammonium nitrate.
moles in 5000 kg of ammonium nitrate :
( molecular mass of ammonium nitrate is 80 gm/mol )
So, number of moles of nitric acid required are also 62500 moles.
Mass of 62500 moles of nitric acid :
Hence, this is the required solution.
Answer:
H-BI,H-Se,H-S,H-I,H-Br
Explanation:
One thing that must be kept in mind is that atomic size increases down the group and decreases across the period. The bond lengths of species are influenced by the relative sizes of atoms or ions present in the bond.
The bonds in the answer have been arranged on basis of their decreasing atomic size because the greater the atomic size of the atoms, the greater the bond length and vice versa.
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<u>Given: </u>
Radius of culvert, r = 0.5 m
Tangential acceleration of the truck, a = 3 m/s2
<u>To determine:</u>
The angular acceleration, α
<u>Explanation:</u>
The tangential acceleration is related to the angular acceleration through the radius as:
a = rα
α = a/r = 3 ms⁻²/0.5 m = 6 s⁻²
Ans: The angular acceleration is 6 s⁻²
