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never [62]
3 years ago
10

The nucleus contains protons and neutrons. Being positively charged, the protons repel each other. The nucleus should fly apart

due to the repulsive force. Yet, the nuclei of most atoms are stable - explain. (5 points)
Physics
1 answer:
Arte-miy333 [17]3 years ago
6 0

this is due to the existence of other forces called the strong nuclear forces that overcomes the repulsion forces between the protons and keeps the nucleons holding to each other also there is a type of energy that is called the nuclear binding energy and this energy also works on binding the components of the nucleus together

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3 years ago
16. Evaluate the expression below if<br> a = -8, b = 17, and c = 21<br> az - (b + c)
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The primary cause of weather is due to ______
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3 years ago
What fraction of an iceberg is submerged? (ρice = 917 kg/m3, ,ρsea = 1030 kg/m3.)
aksik [14]

Answer:

Choice d. Approximately 89\% of the volume of this iceberg would be submerged.

Explanation:

Let V_\text{ice} denote the total volume of this iceberg. Let V_\text{submerged} denote the volume of the portion that is under the liquid.

The mass of that iceberg would be \rho_\text{ice} \cdot V_\text{ice}. Let g denote the gravitational field strength (g \approx 9.81\; \rm N \cdot kg^{-1} near the surface of the earth.) The weight of that iceberg would be: \rho_\text{ice} \cdot V_\text{ice} \cdot g.

If the iceberg is going to be lifted out of the sea, it would take water with volume V_\text{submerged} to fill the space that the iceberg has previously taken. The mass of that much sea water would be \rho_\text{sea} \cdot V_\text{submerged}.

Archimedes' Principle suggests that the weight of that much water will be exactly equal to the buoyancy on the iceberg. By Archimedes' Principle:

\text{buoyancy} = \rho_\text{sea} \cdot V_\text{submerged} \cdot g.

The buoyancy on the iceberg should balance the weight of this iceberg. In other words:

\underbrace{\rho_\text{ice} \cdot V_\text{ice} \cdot g}_\text{weight of iceberg} =  \underbrace{\rho_\text{sea} \cdot V_\text{submerged} \cdot g}_\text{buoyancy on iceberg}.

Rearrange this equation to find the ratio between V_\text{submerged} and V_\text{ice}:

\begin{aligned} &\frac{V_\text{submerged}}{V_\text{ice}} \\&= \frac{\rho_\text{ice} \cdot g}{\rho_\text{sea} \cdot g}\\ &= \frac{\rho_\text{ice}}{\rho_\text{sea}}\ = \frac{917\; \rm kg \cdot m^{-3}}{1030\; \rm kg \cdot m^{-3}} \approx 0.89 \end{aligned}.

In other words, 89\% of the volume of this iceberg would have been submerged for buoyancy to balance the weight of this iceberg.

8 0
3 years ago
You throw a ball straight up at 45 m/s. how many seconds elapse before it is traveling downward at 9 m/s?
NeTakaya

In order to change from 45 m/s up to 9 m/s down, the velocity
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So the change takes  (54/9.8)  =  5.5 seconds .
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3 years ago
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