Answe 174.0 KPA
Explanation:
0°C in 101.3 K PA pressure a sample of gas occupies 30 mL if the temperature is increased to 30°C in the entire gas sample is transferred to a 20 mL container what will be the gas pressure inside a container
PV=nRTt
so
n = PV/RT
P = 101.3 KPA
T = 0+273.2 = 273.200
V = (30/1000) L = 0.03 L
R =0.082
SO
n= (101.3 X 0.03)/(0.082 X 273.2)
= 0.14 moles
PV= nRT
N= 0,14
T = 30 + 273.2= 303.2
V= (20/1000)L =0.02L
since PV = nRT
THEN
P=nRT/V
so
P=(0.14 X 0.082 X 303.2)/0.02 =
174.0 KPA
Answer:
D 2,2
Explanation:
We can see that there are 2 chlorines on the reactant side so there has to be a 2 on the product side
Now we have Na + Cl2 --> 2NaCl
The problem now is that there are 2 sodiums on the product side so add a 2 to the Na on the reactant side
2Na + Cl2 --> 2NaCl
Now it's balanced!
Answer:
98.68%
Explanation:
Step 1: Write the balanced equation
KBr + AgNO₃ ⇒ AgBr + KNO₃
Step 2: Calculate the moles corresponding to 814.5 mg (0.8145 g) of AgBr
The molar mass of AgBr is 187.77 g/mol.
0.8145 g × 1 mol/187.77 g = 4.338 × 10⁻³ mol
Step 3: Calculate the moles of KBr needed to produce 4.338 × 10⁻³ moles of AgBr
The molar ratio of KBr to AgBr is 1:1. The moles of KBr needed are 1/1 × 4.338 × 10⁻³ mol = 4.338 × 10⁻³ mol.
Step 4: Calculate the pure mass corresponding to 4.338 × 10⁻³ moles of KBr
The molar mass of KBr is 119.00 g/mol.
4.338 × 10⁻³ mol × 119.00 g/mol = 0.5162 g
Step 5: Calculate the purity of KBr
0.5162 g of KBr are in a 0.5231 g-sample. The purity of KBr is:
P = 0.5162 g/0.5231 g × 100% = 98.68%
Answer:
Substrate D
Explanation:
In substitution reactions the tertiary substrates cannot undergo substitution via neighboring group participation (NGP) due to the steric impediment, this means that the volume occupied by the substituents is very large and makes it impossible to attack the nucleophile to the substrate carbon.
Answer:
glucosa
En la fotosíntesis, la energía solar se recolecta y se convierte en energía química en forma de glucosa utilizando agua y dióxido de carbono. El oxígeno se libera como subproducto.
Explanation: