I’m pretty sure it’s true
The Boiling Point of 2-methylpropane is approximately -11.7 °C, while, Boiling Point of <span>2-iodo-2-methylpropane is approximately 100 </span>°C.
As both compounds are Non-polar in nature, So there will be no dipole-dipole interactions between the molecules of said compounds.
The Interactions found in these compounds are London Dispersion Forces.
And among several factors at which London Dispersion Forces depends, one is the size of molecule.
Size of Molecule:
There is direct relation between size of molecule and London Dispersion forces. So, 2-iodo-2-methylpropane containing large atom (i.e. Iodine) experience greater interactions. So, due to greater interactions 2-iodo-2-methylpropane need more energy to separate from its partner molecules, Hence, high temperature is required to boil them.
Explanation:
Standardization is the process of creating protocols to guide the creation of a good or service based on the consensus of all the relevant parties in the industry. ... Standardization also helps in ensuring the safety, interoperability, and compatibility of goods produced.
<u>Answer:</u> It repels positive ion and attracts negative ion.
<u>Explanation:</u>
There are 2 types of ions:
1. Cations: These ions are positively charged ions which are formed when a substance looses electrons.
2. Anions: These ions are negatively charged ions which are formed when a substance gains electrons.
It is known that, like charges repel each other and unlike charges attract each other.
As, it is given that the substance is positively charged, so it will attract anion and repel cation.
Answer:
Lavoisier made an important contribution to chemistry by the law of conservation of mass
Explanation:
The law of conservation of mass tell us, that the mass doens't change in a system. You have the same mass at the begining and in the end of a reaction.
Matter is neither created, nor destroyed in a chemical reaction.
This law also states that mass of reactants is the same of products in any chemical reaction
