X-2=10
or
10=x-2
this is because it says "2 less than a number is 10" so we can infer that 2 is less than a number (x) so knowing that less than means subtract x-2=10 or you can put it as 10=x-2
Answer: the equation is 2n-10
Please, use parentheses to enclose each fraction:
y=3/4X+5 should be written as <span>y=(3/4)X+5
Let's eliminate the fraction 3/4 by multiplying the above equation through by 4:
4[y] = 4[(3/4)x + 5]
Then 4y = 3x + 20
(no fraction here)
Let 's now solve the system
4y=3x + 20
4x-3y=-1
We are to solve this system using subtraction. To accomplish this, multiply the first equation by 3 and the second equation by 4. Here's what happens:
12y = 9x + 60 (first equation)
16x-12y = -4, or -12y = -4 - 16x (second equation)
Then we have
12y = 9x + 60
-12y =-16x - 4
If we add here, 12y-12y becomes zero and we then have 0 = -7x + 56.
Solving this for x: 7x = 56; x=8
We were given equations
</span><span>y=3/4X+5
4x-3y=-1
We can subst. x=8 into either of these eqn's to find y. Let's try the first one:
y = (3/4)(8)+5 = 6+5=11
Then x=8 and y=11.
You should check this result. Subst. x=8 and y=11 into the second given equation. Is this equation now true?</span>
Answer:
m∠KIJ = m∠LIM ⇒ answer B
Step-by-step explanation:
* Lets explain how to solve the problem
∵ I is the mid-point of NH
∴ IN = IH
- MJ is perpendicular to NH and passes through I the mid-point of NH
∴ MJ is perpendicular bisector of NH
- NH ⊥ MJ and intersects it at I
∴ m∠NIM = m∠NIJ = 90°
- ∠ NIM consists of two angles ∠NIL and ∠MIL
∵ m∠NIM = m∠NIL + m∠MIL
- ∠NIJ consists of two angles ∠NIK and ∠JIK
∵ m∠NIJ = m∠NIK + m∠JIK
∴ m∠NIL + m∠MIL = m∠NIK + m∠JIK ⇒ (1)
∵ NH bisects ∠KIL
∴ m∠NIL = m∠NIK ⇒ (2)
- From (1) and (2)
∴ m∠MIL = m∠JIK
* m∠KIJ = m∠LIM
Answer:
the answer is 2
Step-by-step explanation:
