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3 years ago

If a quadrilateral has sides that measure 4 in and angles that all measure 90 we can consider the quadrilateral to be a??

2 answers:

7 0

If all side measure are the same, it can be a square or rhombus. If all angles measure 90 degrees, then it is a square.

svp [43]3 years ago

5 0

You can consider it to be a square

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The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

3 years ago

What is the domain of y=log(x+2)

Andru [333]

Answer:

$\huge\boxed{x>-2\to x\in(-2;\ \infty)}$

Step-by-step explanation:

$y=\log(x+2)\\\\\bold{Domain:}\\\\x+2>0\qquad|\text{subtract 2 from both sides}\\\\x+2-2>0-2\\\\x>-2$

8 0

3 years ago

How to write fractions

wolverine [178]

If you are talking about on Brainly.com it is like this.

To write half write 1/2 (1 forward slash 2)

8 0

3 years ago

Solve the system using elimination.

Shalnov [3]

Answer:

After simplifying we get (x,y) as (1,3).

Step-by-step explanation:

Given:

$x+7y=22$ ,

$x-7y=-17$

We need to use elimination method to solve the and simplify the equations.

Solution;

Let $x+7y=22$ ⇒ equation 1

Also Let $4x-7y=-17$ ⇒ equation 2

Now by solving the equation we get;

first we will Add equation 2 from equation 1 we get;

$(x+7y)+(4x-7y)=22+(-17)\\\\x+7y+4x-7y=22-17\\\\5x=5$

Now Dividing both side by 5 using division property of equality we get;

$\frac{5x}{5}=\frac{5}{5}\\\\x=1$

Now Substituting the vale of x in equation 1 we get;

$x+7y=22\\\\1+7y=22$

subtracting both side by 1 using subtraction property of equality we get;

$1+7y-1=22-1\\\\7y=21$

Now Dividing both side by 7 using division property of equality we get;

$\frac{7y}{7}=\frac{21}{7}\\\\y=3$

Hence we can say that, After simplifying we get (x,y) as (1,3).

4 0

3 years ago

What are the coordinates of the point (−1, 6) after a reflection across the x-axis?

Agata [3.3K]

The answer would be (-1,-6). Remember that the x-axis runs left to right and the y-axis runs up and down. Therefore, if you were to reflect it, just picture it being flipped over. If you go from (-1,+6) and you reflect it over the x-axis, both points are now in the bottom left quadrant where everything is negative. So, you get (-1,-6) The -1 doesn't change since it was already a -x value before and stayed in a negative area.

3 0

3 years ago