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3 years ago

create a sketch of the graph of a function whose gradient is linear and that gradient has an x-intercept at x=4

Mathematics

1 answer:

valentina_108 [34]3 years ago

7 0

Here is one that meets your requirements.

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A barn silo (except the top) is a cylinder. The silo is 10 m in diameter and the height is 24. What's the volume? (use 3.14 for

madreJ [45]

Volume of cylinder= /pi r square h

Taking /pi as 22/7

r= diameter/2

=5m

h=24m

V= 22/7*5 square*24

V=22*25*24/7

V=13200/7

V=1885.7 m cube

8 0

3 years ago

Solve for x ....... thanks !

Len [333]

If we can match teh bases we can solve
because if x=x and xᵃ=xᵇ, we can conclude that a=b

16=2⁴
32=2⁵
rememeber that $(x^m)^n=x^{mn}$

$16^{3x+2}=32^{-2x-7}$
$(2^4)^{3x+2}=(2^5)^{-2x-7}$
$2^{4(3x+2)}=2^{5(-2x-7)}$
2=2 so we conclude that 4(3x+2)=5(-2x-7)

4(3x+2)=5(-2x-7)
expand/distribute
12x+8=-10x-35
add 10x both sides
22x+8=-35
minus 8 both sides
22x=-43
divide both sides by 22
x=-43/22

8 0

2 years ago

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

A cone has a volume of 942 in.³ and a height of 9 inches what is the radius of the cone use 3.14 for pie

bija089 [108]

Answer:

r = 51.96 inches

Step-by-step explanation:

$V_{cone} = \pi {r}^{2} h \\ \\ \implies \: r^{2} = \frac{V_{cone}}{\pi h } \\ \\ \implies \: r^{2} = \frac{942}{3.14 {(9) } }\\ \\ \implies \: r^{2} = \frac{942}{3.14 {(9) } } \\ \\ \implies \: r^{2} =2700 \\ \\ \implies \: r= \sqrt{2700} \\ \\ \implies \: r=51.96 \: inches$

8 0

2 years ago

DUE TODAY NO LINKS OR FILES

kupik [55]

64 dollars is the answer

4 0

2 years ago

Read 2 more answers