Answer:
<u>Frequency</u>- number of wave cycles that occur in a given amount of time.
<u>Pitch</u>- number of wavelengths in a given amount of time.
<u>Amplitude</u>- fluctuation or displacement of a wave from its mean value. That means how high or low they are away from the center line.
<u>Volume</u>- The perception of loudness from the intensity of a sound wave. The higher the intensity of a sound, the louder it is perceived in our ears, and the higher volume it has.
<u>Wavelength</u>- the distance between the tops of the "waves".
Answer:
11. 5 N to the left.
12. 10 N to the right.
Explanation:
11. Determination of the net force.
Force in the left direction (Fₗ) = 10 N
Force in the right direction (Fᵣ) = 5 N
Net force (Fₙ) =?
The net force can be obtained as follow:
Fₙ = Fₗ – Fᵣ (Since the forces act in opposite direction)
Fₙ = 10 – 5
Fₙ = 5 N to left
Thus, the net force is 5 N to the left.
12. Determination of the net force.
Force in the right direction 1 (Fᵣ₁) = 5 N
Force in the right direction 2 (Fᵣ₂) = 5 N
Net force (Fₙ) =?
The net force can be obtained as follow:
Fₙ = Fᵣ₁ + Fᵣ₂ (Since the forces act in the same direction)
Fₙ = 5 + 5
Fₙ = 10 N to the right
Thus, the net force is 10 N to the right.
Newton's 2nd law of motion:
Net Force = (mass) x (acceleration) .
The law shows the relationship among an object's mass
and acceleration, and the net force acting on it.
If you know any two of the quantities in the formula,
the law can be used to calculate the third one.
force goes as 1/d^2 ... (2d)^2 => 4d^2 ...
C) decrease by a factor of four
Answer:
(orbital speed of the satellite) V₀ = 3.818 km
Time (t) = 4.5 × 10⁴s
Explanation:
Given that:
The radius of the Earth is 6.37 × 10⁶ m; &
the acceleration of gravity at the satellite’s altitude is 0.532655 m/s
We can calculate the orbital speed of the satellite by using the formula:
Orbital Speed (V₀) = √(r × g)
radius of the orbit (r) = 21000 km + 6.37 × 10⁶ m
= (2.1 × 10⁷ + 6.37 × 10⁶) m
= 27370000
= 2.737 × 10⁷m
Orbital Speed (V₀) = √(r × g)
Orbital Speed (V₀) = √(2.737 × 10⁷ × 0.532655 )
= 3818.215
= 3.818 × 10³
= 3.818 Km
To find the time it takes to complete one orbit around the Earth; we use the formula:
Time (t) = 2 π ×
= 2 × 3.14 ×
= 45019.28
= 4.5 × 10 ⁴ s