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vampirchik [111]
3 years ago
6

An elderly sailor is shipwrecked on a desert island but manages to save his eyeglasses. The lens for one eye has a power of 1.16

diopters, and the other lens has a power of 9.37 diopters. What is the magnifying power of the telescope he can construct with these lenses
Physics
1 answer:
igomit [66]3 years ago
8 0

Answer:

m = 8

Explanation:

A telescope is a device that allows us to see objects that were very far from us, it is built by the combination of two lenses, the one with the lowest focal length near the eye and that is the one or the one with the greatest focal length, the most eye-flounder . The magnification of the telescope is

            m = - f₀ / f_{e}

Where f₀ is the focal length of the lens and f_{e} is the false distance of the eyepiece.

It is this problem that gives us the diopter of each lens, these are related to the focal length in meters

           D = 1 / f

Let's find the focal length

       f₁ = 1 / D₁

       f₁ = 1 / 1.16

       f₁ = 0.862 m

     

        f₂ = 1 / 9.37

        f₂ = 0.1067 m

Therefore, the lens with f₂ is the eyepiece and the slow one with the  

distance focal  f₁ is the objective.

Let's calculate

       m = - f₂ / f₁

      m = - 0.862 / 0.1067

      m = 8

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Answer:

option (E) is correct.

Explanation:

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force, f = 100 N

Coefficient of friction, = 0.25

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So, net force F = f - friction force

F = 100 - 0.25 x m g

Work = (100 - 0.25 mg) x d cosθ

For minimum work, the angle should be maximum.

So, the value of θ is 76°.

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3 0
3 years ago
A series circuit contains a 9-volt battery, a 3-ohm resistor and a 2-ohm resistor. What is the voltage drop across the 2-ohm res
BARSIC [14]
Since everything in the circuit is in series .. .

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-- The voltage across the 3-ohm resistor is 3/5 of the total voltage.

-- The voltage across the 2-ohm resistor is 2/5 of the total voltage.

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7 0
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sleet_krkn [62]
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Calculate the pressure the fluid exerted on your diver. The acceleration of gravity is 9.8 m/s2 and the density of the water is
erica [24]

Complete question:

A diver is 10 m below the surface of water. Calculate the pressure the fluid exerted on the diver. The acceleration of gravity is 9.8 m/s2 and the density of the water is 1000 kg/m3. Answer in units of Pa. Show your work.

Answer:

Tthe pressure the fluid exerted on the diver is 1.99 x 10⁵ Pa

Explanation:

Given;

density of water, ρ = 1000 kg/m³

diver's position below the surface of the water, h = 10 m

acceleration due to gravity, g = 9.8 m/s²

Let the atmospheric pressure, P₀ = 101325 Pa

The pressure 10 m below the surface of the water is calculated as;

P =  P₀  + ρgh

P = 101325 Pa  +  (1000 x 9.8 x 10)Pa

P = 199325 Pa

P = 1.99 x 10⁵ Pa.

Therefore, the pressure the fluid exerted on the diver is 1.99 x 10⁵ Pa

5 0
3 years ago
The force between two charges, q, and 92, is F. If the distance between the
Sholpan [36]

Answer:

4F

Explanation:

F = kQ₁Q₂/d²

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