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vampirchik [111]
2 years ago
6

An elderly sailor is shipwrecked on a desert island but manages to save his eyeglasses. The lens for one eye has a power of 1.16

diopters, and the other lens has a power of 9.37 diopters. What is the magnifying power of the telescope he can construct with these lenses
Physics
1 answer:
igomit [66]2 years ago
8 0

Answer:

m = 8

Explanation:

A telescope is a device that allows us to see objects that were very far from us, it is built by the combination of two lenses, the one with the lowest focal length near the eye and that is the one or the one with the greatest focal length, the most eye-flounder . The magnification of the telescope is

            m = - f₀ / f_{e}

Where f₀ is the focal length of the lens and f_{e} is the false distance of the eyepiece.

It is this problem that gives us the diopter of each lens, these are related to the focal length in meters

           D = 1 / f

Let's find the focal length

       f₁ = 1 / D₁

       f₁ = 1 / 1.16

       f₁ = 0.862 m

     

        f₂ = 1 / 9.37

        f₂ = 0.1067 m

Therefore, the lens with f₂ is the eyepiece and the slow one with the  

distance focal  f₁ is the objective.

Let's calculate

       m = - f₂ / f₁

      m = - 0.862 / 0.1067

      m = 8

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Tendons are strong elastic fibers that attach muscles to bones. To a reasonable approximation, they obey Hooke's law. In laborat
meriva

Answer:

k = 200 N/m

Explanation:

given,

mass of the object  = 251 g

                                = 251 x 10⁻³ Kg = 0.251 Kg

distance of tendon stretch = x = 1.23 cm

                                            = 1.23 x 10⁻² = 0.0123 m

using the formula

F = k  x

where

k is the force constant of the tendon

F = m g

F = 0.251 x 9.8 = 2.4598 N

2.4598 = k x 0.0123

k = 199.98 N/m

k = 200 N/m

hence, force constant of the tendon is approximately equal to 200 N/m

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8 0
3 years ago
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A railroad car of mass 2.50*10^4 kg is moving with a speed of 4.00 m/s. It collides and couples with three other coupled railroa
NemiM [27]

Answer:

(a) 2.5 m/s

(b) 37.5 KJ

Explanation:

(a)

From the law of conservation of momentum, Initial momentum=Final momentum

mV_1+3mV_2=(m+3m)V_f=4mV_f

V_1+3V_2=4V_f and making V_f the subject then

V_f=\frac {V_1+3V_2}{4} and since V_1 is initial velocity of car, value given as 4 m/s, V_2 is the initial velocity of the three cars stuck together, value given as 2 m/s and v_f is the final velocity which is unknown. By substitution

V_f=\frac {4+(3\times2)}{4}=2.5 m/s

(b)

Initial kinetic energy is given by

\frac {mV_1^{2}}{2}+\frac {3mV_2^{2}}{2}=\frac {m(V_1^{2}+3V_2^{2}}{2}=\frac {2.5\times 10^{4}(4^{2}+3(2^{2}))}{2}=350\times10^{3} J= 350 KJ

Final kinetic energy is given by

\frac {4mV_f^{2}}{2}=\frac {4\times 2.5\times 10^{4}\times 2.5^{2}}{2}=312.5\times 10^{3} J=312.5 KJ

The energy lost is given by subtracting the final kinetic energy from the initial kinetic energy hence

Energy lost=350-312.5=37.5 KJ

6 0
3 years ago
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Calculate the average velocity of a dancer who moves 5 m toward the left of the stage over the course of 15 s. ** Velocity = dis
Alex73 [517]

Answer:

B

Explanation:

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3 years ago
A person kicks a 4.0-kilogram door with a 48-newton force causing the door to accelerate at 12 meters per second squared. What i
inna [77]

Answer:

-48 N

Explanation:

mass of door (m) = 4 kg

acceleration of the door = 12 m/s^{2}

force exerted by the person = 48 N

From Newton's third law of motion, action and reaction are equal but opposite. Therefore the force exerted on the door by the person which is 48 N will be the same as the force exerted on the person by the door but opposite in its direction, and this would be - 48 N

7 0
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