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Feliz [49]
3 years ago
7

A(n) ______ particle consists of two protons and neutrons.

Physics
1 answer:
mamaluj [8]3 years ago
7 0
The answer would be an alpha particle because the beta particle doesn't carry the amount of protons and neutrons.
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Yasmin determines the velocity of a car to be 15m/s. The accepted value for the velocity of the car is 15.6m/s. What is yasmins
zaharov [31]

Percent error is calculated as follows:

% = ( |15-15.6| / 15.6 ) *  100%

% = (0.6/15.6) * 100%

% = 0.0385 * 100%

% = 3.85%

Hope this helped!

7 0
3 years ago
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What is he total resistance?<br> A. 20 ohms<br> B. 90 ohms<br> C. 40 ohms<br> D. 30 ohms
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Imma guess A! Idk if it’s 100% correct tho so I’d check that!
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A regular polygon has angkes of size 150° each.how many side has the polygon​
emmasim [6.3K]

Answer: 12

Explanation:

ıf each interior is 150 degrees, then each exterior angle is 180–150 or 30 degrees. Hence the polygon has 360/30 = 12 sides

5 0
3 years ago
Iii A load of 2.5 N is hung on the spring.
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3 years ago
A physics book slides off a horizontal tabletop with a speed of 1.10 m/s. It strikes the floor in 0.350s. ignore air resistance.
Nookie1986 [14]

Answer:

a. 0.6 m b. 0.385 m c. 3.6 m/s at 287.78° to the horizontal

Explanation:

a. Using s = ut - 1/2gt² for motion under gravity where s = vertical distance = height of table, u = initial vertical velocity of book = 0 m/s, t = time of flight = 0.350 s and g = acceleration due to gravity = 9.8 m/s².

Substituting these these values into s and taking the top of the table as position 0 m, we have.

0 - s = 0t - 1/2gt²

-s = -1/2gt²

s = 1/2gt²

s = 1/2 × 9.8 m/s² × (0.350 s)²

s = 0.6 m

b. Using d = v't where d = horizontal distance from table, v' = horizontal velocity of book = 1.10 m/s and t = time of flight = 0.350 s

d = v't = 1.10 m/s × 0.350 s = 0.385 m

c. Using v² = u² - 2gs where u = initial vertical velocity of book = 0 m/s and g = 9.8 m/s², s = -0.6 m (negative since we are at the bottom and 0 m is at the top)and v = final vertical velocity of book

v² = u² - 2gs

= 0 - 2 × 9.8 m/s² × (-0.6 m)

= 11.76 m²/s²

v = √11.76 m/s

= 3.43 m/s

So, the magnitude of the resultant velocity is V = √(v² + v'²)

= √((3.43 m/s)² + (1.10 m/s)'²)

= √(11.76 m²/s² + 1.21 m²/s²)

= √12.97 m²/s²

= 3.6 m/s

Its direction Ф = tan⁻¹(-v/v') since v is in the negative y direction

= tan⁻¹(-3.43 m/s/1.10 m/s)

= tan⁻¹(-3.1182)

= -72.22°

Ф = -72.22°+ 360 = 287.78° since it is in the third quadrant

7 0
3 years ago
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