Answer:
Your answer would be C <u><em>Hope this helps</em></u>
Answer:
9.9 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
![v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 5+0^2}\\\Rightarrow v=9.9\ m/s](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2as%2Bu%5E2%7D%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2%5Ctimes%209.81%5Ctimes%205%2B0%5E2%7D%5C%5C%5CRightarrow%20v%3D9.9%5C%20m%2Fs)
If the body has started from rest then the initial velocity is 0. In order to find the velocity just before hitting the water then the distance at which the downward motion stops is irrelevant.
Hence, the speed of the diver just before striking the water is 9.9 m/s
Answer:
Volume, V = 13564.8 cubic feet
Explanation:
It is given that,
Radius of the cylindrical tank, r = 12 feet
Height of the tank, h = 30 feet
We need to find the water that can be held by a cylindrical tank i.e. we need to find the volume of the tank. It is given by :
![V=\pi\times r^2\times h](https://tex.z-dn.net/?f=V%3D%5Cpi%5Ctimes%20r%5E2%5Ctimes%20h)
![V=3.14\times (12)^2\times 30](https://tex.z-dn.net/?f=V%3D3.14%5Ctimes%20%2812%29%5E2%5Ctimes%2030)
V = 13564.8 cubic feet
So, the water held by the tank is 13564.8 cubic feet. Hence, this is the required solution.