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dusya [7]
4 years ago
12

Yasmin determines the velocity of a car to be 15m/s. The accepted value for the velocity of the car is 15.6m/s. What is yasmins

percent error ?
Physics
2 answers:
zaharov [31]4 years ago
7 0

Percent error is calculated as follows:

% = ( |15-15.6| / 15.6 ) *  100%

% = (0.6/15.6) * 100%

% = 0.0385 * 100%

% = 3.85%

Hope this helped!

densk [106]4 years ago
6 0

For this case we have that the percentage of error is given by the following equation:

percent\ error= \frac {|v_ {a} -v_ {e}|} {v_ {e}} * 100

Where:

v_ {a}: Approximate (measured) value: 15

v_ {e}:Exact value: 15.6

Substituting:

percent\ error= \frac {| 15-15.6 |} {15.6} * 100\\percent\ error = \frac {0.6} {15.6} * 100\\% error = 3.85

Thus, the percentage of error is 3.85%

Answer:

3.85%

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What is the pressure drop due to the bernoulli effect as water goes into a 3.00-cm-diameter nozzle from a 9.00-cm-diameter fire
Paul [167]

Answer:

\Delta P=1581357.92\ Pa

Explanation:

Given:

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<u>Now, flow velocity in hose:</u>

v_h=\frac{\dot V}{\pi.D^2\div 4}

v_h=\frac{0.04\times 4}{\pi\times 0.09^2}

v_h=6.2876\ m.s^{-1}

<u>Now, flow velocity in nozzle:</u>

v_n=\frac{\dot V}{\pi.d^2\div 4}

v_n=\frac{0.04\times 4}{\pi\times 0.03^2}

v_n=56.5884\ m.s^{-1}

We know the Bernoulli's equation:

\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}+Z_1=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}+Z_2

when the two points are at same height then the eq. becomes

\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}

\Delta P=\frac{\rho(v_n^2-v_h^2)}{2}

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8 0
3 years ago
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EastWind [94]

Answer:

(a) Total time will be 8.05 hour

(B) Total cost will be $417.6                

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Time t = 45 minutes =45×60 = 2700 sec

So power P = VI = 240×16 = 3840 W

So energy E = power×time = 3840×45×60 = 9396 KJ

(A) Now current in the computer i = 2.7 A

Voltage V = 120 V

So power P = 120×2.7 = 324 W

Now computer is using energy of dryer

So time by which it will use energy is t=\frac{9396000}{324}=29000sec=8.05hour

So time will be 8.05 hour

(b) Cost per kilowatt is $0.12

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4 0
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nignag [31]

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ii) Inside the sphere,

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iii) Outside the sphere at distance 15cm

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5 0
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