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Degger [83]
3 years ago
12

Jamie dropped a water bottle from the top of an office building. The water bottle impacted the ground after falling for 5 second

s. Calculate the velocity of the water bottle at impact with the street below.
Physics
1 answer:
PSYCHO15rus [73]3 years ago
4 0

Answer:

<em>The speed of the water bottle at impact with the street is 49 m/s</em>

Explanation:

<u>Free Fall Motion </u>

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not experience air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is g = 9.8 m/s^2.

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The water bottle dropped by Jamie takes t=5 seconds to impact the ground, thus its speed at that moment is:

vf= 9.8*5

vf =  49 m/s

The speed of the water bottle at impact with the street is 49 m/s

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Anon25 [30]

Answer:

D. Principle of original horizontality

B. Principle of faunal succession

A. Uniformitarianism

C. Principle of superposition

Explanation:

Question 1

The principle of original horizontality is one of the foremost relative dating principle that is wide used in stratigraphy.

It states that "sedimentary rocks are laid down flatly on top one another in a sedimentary basin".

Sedimentary rocks will only vary vertically, but laterally, they are uniform and internally homogeneous in space. This is why most sedimentary rocks are stratified and laid layers upon layers just like the pages of a book.

Each layer is called a bed and often times are laterally continuous in space within the same basin.

Whenever we see beds not horizontally continuous, we can conclude that a tectonic event must have disrupted the sequence and it came after the it was formed.

Question 2

Principle of faunal succession succession was proposed by Williams Smith, an English Geologist and a canal worker in the 19th century.

Based on this principle, sedimentary rocks can placed in their proper chronostratigrahic framework based on the fossils they contain in them.

  • This principle is hinged on theory of evolution.
  • It is widely accepted that organisms evolved from one another.
  • Rocks often bear these records in fossil remains and this can help us appropriately fit rocks to the time they were formed.

Question 3

The principle of uniformitarianism was one of the disruptive proposition in earth science.

A Scottish name James Hutton while in the country side made this proposition as he observed how landform in his native changed with each episode of season.

The principle proposes that "the processes occurring today have occurred in the time past at the same rate".

This way, it was much more easier to understand how land changes in pre-historic times have occurred.

Before his theory, the principle of catastrophism was the widely accepted one. This theory suggested that events occurred rapidly and changes to the surface are much more faster.

Question 4

The principle of superposition is one of the relative dating principles. It proposes that "in an undeformed land sequence, the oldest rock is at the bottom and the youngest on top".

The first sediment to get deposited fills the bottom as it aggregates upward. This leaves the youngest lithology to the top of strata.

The principle is correct for undeformed or undisturbed rock strata.

Where the sediments are disturbed, the formation might be overturned and this principle might be difficult to apply.

3 0
3 years ago
As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.15 mm apart and position
Artist 52 [7]

Answer:

The distance of the first bright fringe is given as  Y_C = 1.22 *10^{-3}m

The distance of the second dark fringe from the central bright fringe is given as  Y_D = 0.00192 \ m

Explanation:

From the question we are told that

     The slit separation distance is  d = 1.15 mm = \frac{1.15}{1000} =0.00115 m

      The distance of the slit from the screen is  D = 3.23 m

        The wavelength is \lambda  = 633 nm

For constructive interference to occur the distance between the two slit is mathematically represented as

            Y_C  =\frac{m \lambda D}{d}

 Where m is the order of the fringe which has a value of 1 for first bright fringe

    Substituting  values

               Y_C = \frac{1 * 633 *0^{-9} * 3.23}{0.00115}

                Y_C = 1.22 *10^{-3}m

For destructive  interference to occur the distance between the two slit is mathematically represented as

            Y_D  =  [n + \frac{1}{2} ] \frac{\lambda D}{d}

      m = 2

so the formula to get the dark fringe is n = \frac{1}{2} * 1

                                                                 n=1

 Now substituting values

                 Y_D = [ 1 + \frac{1}{2} ] * \frac{633 *10^{-9} * 3.23 }{0.00115}

                   Y_D =1.5 * \frac{633 *10^{-9} * 3.23 }{0.00115}

                        Y_D = 0.00192 \ m

4 0
3 years ago
A-delta fibers : A) are small, myelinated fibers. B) transmit pain signals at a slower rate than C-fibers. C) typically transmit
daser333 [38]

Answer:

A

Explanation:

Aδ fibers carry cold, pressure, and acute pain signals, and because they are thin (2 to 5 μm in diameter) and myelinated, they send impulses faster than unmyelinated C fibers, but more slowly than other, more thickly myelinated group A nerve fibers. Their conduction velocities are moderate.

7 0
3 years ago
A tall tube is evacuated and its stopcock is closed. The open end of the tube is immersed in a container of water (density 10^3
LuckyWell [14K]

Answer:

10.19 m

Explanation:

Water will rise to equalize the pressure inside and outside the tube.

The equation of pressure is given by

p=\rho gh

Where,

p = Pressure of air = 10⁵ N/m²

ρ = Density of water = 10³ kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Height the water will rise

h=\frac{p}{gh}\\\Rightarrow h=\frac{10^5}{9.81\times 10^3}\\\Rightarrow h=10.19\ m

∴ The water will rise by 10.19 m.

7 0
3 years ago
If you went to a planet that had the twice the radius as Earth, but the same mass, a 1 kg pineapple would have a weight of
kicyunya [14]

Use the law of universal gravitation, which says the force of gravitation between two bodies of mass <em>m</em>₁ and <em>m</em>₂ a distance <em>r</em> apart is

<em>F</em> = <em>G m</em>₁ <em>m</em>₂ / <em>r</em>²

where <em>G</em> = 6.67 x 10⁻¹¹ N m²/kg².

The Earth has a radius of about 6371 km = 6.371 x 10⁶ m (large enough for a pineapple on the surface of the earth to have an effective distance from the center of the Earth to be equal to this radius), and a mass of about 5.97 x 10²⁴ kg, so the force of gravitation between the pineapple and the Earth is

<em>F</em> = (6.67 x 10⁻¹¹ N m²/kg²) (1 kg) (5.97 x 10²⁴ kg) / (6.371 x 10⁶ m)²

<em>F</em> ≈ 9.81 N

Notice that this is roughly equal to the weight of the pineapple on Earth, (1 kg)<em>g</em>, where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity, so that [force of gravity] = [weight] on any given planet.

This means that on this new planet with twice the radius of Earth, the pineapple would have a weight of

<em>F</em> = <em>G m</em>₁ <em>m</em>₂ / (2<em>r</em>)² = 1/4 <em>G m</em>₁ <em>m</em>₂ / <em>r</em>²

i.e. 1/4 of the weight on Earth, which would be about 2.45 N.

7 0
3 years ago
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