Answer:
24.15%
Explanation:
According to the given situation the computation of the percent yield of the reaction is shown below:-
PV = NRT = N =
Mole of =
=
=
= 0.0186
Mole of
= 0.077
Now, the percentage of yield is
=
=
= 24.15%
Therefore for computing the percentage of yield we simply divide the practical yield by theoretical yield and multiply with 100 so that we can get the result into the percentage form.
Answer:
your answer second once is correct
Explanation:
don't worry! have a good day dear!!..
Explanation:
Dinitrogen trioxide is a nitrogen oxide. Nitrogen trioxide appears as a blue liquid with a sharp, unpleasant chemical odor.
Description: Dinitrogen trioxide is a nitrogen oxide.ChEBINitrogen trioxide appears as ...
Synonyms: Dinitrogen trioxideNITROGEN TRIOXIDENitrogen oxide (N2O3)10544-7...
Molecular Formula: N2O3
Molecular Weight: 76.012 g/mol
Hey there!:
Given that;
SO2 (g ) = (-296.8 kJ/mol) and SO3 (g )= (-395.7 Kj/mol)
2 SO2(g) + O2(g) --------------> 2 SO3(g)
ΔH reaction = ΔH of product - ΔH of reactant
We know that ΔH O2 = 0 kj
ΔH reaction = [2 x - 395.7] - [2 x - 296.8 +0.0 KJ]
= - 791.4 - (- 593.6)
= - 791.4 + 593.6
= - 197.8 kJ
Because there are 2 mole of SO2 coverted into 2 mole of SO3 :
=- 197.8 kJ/2 mol
ΔH°rxn = - 98.9 kJ/ mol
Hope that helps!