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3 years ago

Suppose a solution has a volume of 2.0 liters. Which amount of solute would produce the most concentrated solution?

2 answers:

6 0

I believe the correct answer from the choices listed above is option A. The amount of solute that would produce the most concentrated solution would be 50 grams. The more of the solute would increase the concentration of the solution. Hope this answers the question.

Tju [1.3M]3 years ago

3 0

A) 50 grams. Because more the amount of substance present in the solution, more concentrated it is.

You might be interested in

Which reagent is the limiting reactant when 0.400 mol Al(OH)3 and 0.400 mol H2SO4 are allowed to react

jeka94

Answer:

H₂SO₄ will be the limiting reagent.

Explanation:

The balanced reaction is:

2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction).

You can use a simple rule of three as follows: if by stoichiometry 2 moles of Al(OH)₃ reacts with 3 moles of H₂SO₄, how much moles of H₂SO₄ will be needed if 0.4 moles of Al(OH)₃ react?

$moles of H_{2} SO_{4} =\frac{0.4 moles of Al(OH)_{3}*3 moles of H_{2} SO_{4} }{2 moles of Al(OH)_{3}}$

moles of H₂SO₄= 0.6 moles

But 0.6 moles of H₂SO₄ are not available, 0.40 moles are available. Since you have less moles than you need to react with 0.4 moles of Al(OH)₃, H₂SO₄ will be the limiting reagent.

7 0

2 years ago

Calculate the mass in grams of 8.35 × 1022 molecules of CBr4.

antiseptic1488 [7]

Answer: 45.983 g CBr₄

Explanation:

To convert from moles to grams, you know that we will need molar mass and Avogadro's number.

Avogadro's number: 6.022×10²³ molecules/mol

Molar mass: 331.627 grams/mol

Now that we have what we need, you can use these to solve for grams. $8.35*10^2^2molecules CBr_{4} *\frac{1mol}{6.022*10^2^3molecules} *\frac{331.627 g}{1 mol} =45.983 g$

Our final answer is 45.983 g CBr₄.

4 0

3 years ago

PLEASE HELP ME!! DIMENSIONAL ANALYSIS CHEMISTRY DUE IN 5 MINS!!!

Eddi Din [679]

Answer:

12 mi/h

Explanation:

Step 1: Given data

Total distance (d): 6 km

Time elapsed (t): 19 min

Step 2: Convert "d" to miles

We will use the conversion factor 1 mi = 1.60934 km.

6 km × 1 mi/1.60934 km = 3.7 mi

Step 3: Convert "t" to hours

We will use the conversion factor 1 h = 60 min.

19 min × 1 h/60 min = 0.32 h

Step 4: Calculate the average speed of the runner (s)

The speed is equal to the quotient between the total distance and the time elapsed.

s = d/t

s = 3.7 mi/0.32 h = 12 mi/h

6 0

3 years ago

What is the slope of a line that is perpendicular to the line shown?

Nonamiya [84]

I think the answer is 3

7 0

3 years ago

Read 2 more answers

Be sure to answer all parts. The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. H2(g) + CO2(g) ⇌ H2O(g) +

nikklg [1K]

Answer:

For 1: The value of $\Delta G$ for the chemical equation is -24.636 kJ/mol

For 2: The value of $\Delta G$ for the chemical equation is -20.925 kJ/mol

Explanation:

For the given chemical equation:

$H_2(g)+CO_2(g)\rightleftharpoons H_2O(g)+CO(g)$

For 1:

To calculate the $\Delta G$ for given value of equilibrium constant, we use the relation:

$\Delta G=-RT\ln K_p$ .....(1)

where,

$\Delta G$ = ? kJ/mol

R = Gas constant = $8.314J/K mol$

T = temperature = 2000 K

$K_p$ = equilibrium constant in terms of partial pressure = 4.40

Putting values in above equation, we get:

$\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (4.40)\\\\\Delta G=-24636.12J/mol$

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -24636.12 J/mol = -24.636 kJ/mol

Hence, the value of $\Delta G$ for the chemical equation is -24.636 kJ/mol

For 2:

The expression of $K_p$ for the given chemical equation is:

$K_p=\frac{p_{CO}p_{H_2O}}{p_{H_2}p_{CO_2}}$

We are given:

$p_{CO}=1.18atm\\p_{H_2O}=0.66atm\\p_{CO_2}=0.82atm\\p_{H_2}=0.27atm$

Putting values in above equation, we get:

$K_p=\frac{1.18\times 0.66}{0.27\times 0.82}\\\\K_p=3.52$

Now, calculating the value of $\Delta G$ by using equation 1:

R = Gas constant = $8.314J/K mol$

T = temperature = 2000 K

$K_p$ = equilibrium constant in terms of partial pressure = 3.52

Putting values in equation 1, we get:

$\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (3.52)\\\\\Delta G=-20925.68J/mol$

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -20925.68 J/mol = -20.925 kJ/mol

Hence, the value of $\Delta G$ for the chemical equation is -20.925 kJ/mol

3 0

3 years ago

Read 2 more answers