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scoundrel [369]
4 years ago
11

Suppose a solution has a volume of 2.0 liters. Which amount of solute would produce the most concentrated solution?

Chemistry
2 answers:
Firlakuza [10]4 years ago
6 0
I believe the correct answer from the choices listed above is option A. The amount of <span> solute that would produce the most concentrated solution would be 50 grams. The more of the solute would increase the concentration of the solution. Hope this answers the question.</span>
Tju [1.3M]4 years ago
3 0
<span>A) 50 grams.  Because more the amount of substance present in the solution, more concentrated it is.</span>
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BARIUM HYDROXIDE IS THE COMPOUND

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kirill115 [55]

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K

Explanation:

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A block of ice has little thermal energy. If you place it in a warm room, it melts into warm liquid water, which has much more e
Naily [24]

<u>Answer:</u>

<em>The energy to turn the ice into water:</em>

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8 0
3 years ago
What mass of Al2(SO4)3 results from mixing 12.93 g of AlCl3 with 10.34 g of (NH4)2SO3 as shown with a 54.2% yield?
avanturin [10]

Mass of Al₂(SO₄)₃ : 4.822 g

<h3>Further explanation  </h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.  

Reaction

2AlCl₃ + 3(NH₄)₂SO₄⇒Al₂(SO₄)₃+ 6NH₄Cl

MW AlCl₃ :133,34 g/mol

MW (NH₄)₂SO₄ : 132,14 g/mol

MW Al₂(SO₄)₃ : 342,15 g/mol

mol  AlCl₃

\tt mol=\dfrac{12.93}{133.34}=0.097

mol (NH₄)₂SO₄

\tt mol=\dfrac{10.34}{132.14}=0.078

Limitng reactants (ratio mol : coefficient = the smaller)

AlCl₃ : (NH₄)₂SO₄ =

\tt \dfrac{0.097}{2}:\dfrac{0.078}{3}=0.0485:0.026

(NH₄)₂SO₄ ⇒ limiting reactants

So mol Al₂(SO₄)₃ from (NH₄)₂SO₄

\tt \dfrac{1}{3}\times 0.078=0.026

mass Al₂(SO₄)₃

\tt 0.026\times 342.15=8.896

with 54.2% yield, the mass of Al₂(SO₄)₃

\tt 0.542\times 8.896=4.822~g

7 0
3 years ago
Please help this will help my grade a lot
vladimir1956 [14]

Answer:

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