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1 year ago

Describe at least four properties of electrons that

1 answer:

6 0

An electron is negatively charged (Thomson), it has a mass approximately 1/2000 that of a hydrogen atom (Millikan), it has a fixed charge-to-mass ratio (Millikan), and it is present in atoms of all elements (Thomson).

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What is the name of the large dome-shaped muscle under your lungs that helps you breathe?

aivan3 [116]

That would be your diaphragm :)

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3 years ago

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Why would dry cleaners use nonpolar tetrachloroethylene, C2Cl4, to get cheeseburger grease out of your clothes?

Kobotan [32]

It is water-soluble. hope this helps

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3 years ago

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An unknown metal has a mass of 86.8 g. When 5040 J of heat are added to the sample, the sample temperature changes by 64.7 ∘ C .

grandymaker [24]

Answer: The specific heat of the unknown metal is $0.897J/g^0C$

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed= $5040$ Joules

m= mass of substance = 86.8 g

c = specific heat capacity = ?

Initial temperature of the water = $T_i$

Final temperature of the water = $T_f$

Change in temperature , $\Delta T=T_f-T_i=(64.7)^0C$

Putting in the values, we get:

$5040=86.8\times c\times 64.7^0C$

$c=0.897J/g^0C$

The specific heat of the unknown metal is $0.897J/g^0C$

4 0

3 years ago

Is o3 inorganic or organic

sammy [17]

Answer:

I'm not sure but I think it's organic

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2 years ago

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2 grams of a substance was dissolved in 75.0 g of water resulting in a temperature decrease from 23.1 ⁰C to 18.7 ⁰C. The specifi

RUDIKE [14]

<h3>Answer:</h3>

1379.4 Joules

<h3>Explanation:</h3>

The quantity of heat is calculated multiplying the mass of a substance by heat capacity and the change in temperature.

Therefore;

Quantity of heat = Mass × specific heat capacity × Change in temperature

Q = mcΔT

In this case;

The substance dissolved in water gained heat while water lost heat energy.

Thus, Heat gained by the substance = heat lost by water

Heat associated with the water

Mass of water = 75 g

Change in temperature = 4.4°C

Specific heat capacity = 4.18 J/g·⁰C

Heat = mcΔT

= 75 g × 4.18 J/g·⁰C × 4.4 °C

=1379.4 Joules

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2 years ago