Explanation:
A Giant Gas Cloud. A star begins life as a large cloud of gas.
A Protostar Is a Baby Star.
The T-Tauri Phase.
Main Sequence Stars.
Expansion into Red Giant.
Fusion of Heavier Elements.
Supernovae and Planetary Nebulae.
The correct answer is B(OH)3 <AI(OH)3 < In(OH)3.
The metallic character of the group 1 elements first increases from Boron to Aluminium, then decreases from Aluminium to Thallium because of high ionization Enthalpy. Also, the larger size of the ion, the lesser is the ionization of Enthalpy.
Basic nature of the hydroxides of group 13 increases on moving down the group as the electro-positive character of elements increases.
Therefore, the correct order of increasing aqueous basicity is as follows:
B(OH)3 <AI(OH)3 < In(OH)3
What is the basic nature of group 13?
The metallic charecter of the elements affects their fundamental characteristics. The basicity rises as the metallic character does, and vice versa. Therefore, as we move lower in any given group, the atomic radius of the elements increases. Higher radii indicate that it would become increasingly challenging for the nucleus to rule over the electrons in the valency shell. Consequently, there will be a greater inclination for electron release. As a result, the metallic properties will improve, increasing the basicity of the oxides. Therefore, it follows that the basicity of the oxides would rise as we go down in a group.
To learn more about hydroxides refer the link:
brainly.com/question/10134219
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Answer:
A reduction potential measures the tendency of a molecule to be reduced by taking up new electrons. ... Standard reduction potentials can be useful in determining the directionality of a reaction. The reduction potential of a given species can be considered to be the negative of the oxidation potential.
Explanation:
The Constitution provides the basic structure for US Government.
As a sidenote, you posted this in Chemistry, when it actually belongs in another topic. Please be sure to post questions only where they belong. Thanks! :)
Answer:
ΔH°rxn = 54.08 kJ
Explanation:
Let's consider the following equations.
a) ClO(g) + O₃(g) ⇄ Cl(g) + 2 O₂(g) ΔH°rxn = –29.90 kJ
b) 2 O₃(g) ⇄ 3 O₂(g) ΔH°rxn = 24.18 kJ
We have to determine the value of heat of reaction for the following reaction: Cl(g) + O₃(g) ⇄ ClO(g) + O₂(g)
According to Hess's law, the enthalpy change in a chemical reaction is the same whether the reaction takes place in one or in several steps. That means that we can find the enthalpy of a reaction by adding the corresponding steps and adding their enthalpies. According to Lavoisier-Laplace's law, if we reverse a reaction, we also have to reverse the sign of its enthalpy.
Let's reverse equation a) and add it to equation b).
-a) Cl(g) + 2 O₂(g) ⇄ ClO(g) + O₃(g) ΔH°rxn = 29.90 kJ
b) 2 O₃(g) ⇄ 3 O₂(g) ΔH°rxn = 24.18 kJ
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Cl(g) + 2 O₂(g) + 2 O₃(g) ⇄ ClO(g) + O₃(g) + 3 O₂(g)
Cl(g) + O₃(g) ⇄ ClO(g) +O₂(g)
ΔH°rxn = 29.90 kJ + 24.18 kJ = 54.08 kJ
