50kg driving at 30kph because it’s the heaviest yet fastest!
This would be a Goal Act Plan, But in translation, Planul Act Gol
Complete Question
A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.
Answer:
The value for static friction is 
The value for static friction is 
Explanation:
From the question we are told that
The mass of the clock is 
The first horizontal force is 
The second horizontal force is 
Generally the static frictional force is equal to the first horizontal force
So

=> 
=> 
Generally the kinetic frictional force is equal to the second horizontal force
So



<span>When taking the reading you must see where the lower meniscus lies . The value at which the lower meniscus lies is your reading .</span>