First, factor out a 3.
3(x² - 9)
In any quadratic ax² + bx + c, we can split the bx term up into two new terms which we want to equal the product of a and c.
In this case, we have x² + 0x - 9. (the 0x is a placeholder)
We want two numbers that add to 0 and multiply to get -9.
Obviously, these numbers are 3 and -3.
Now we have 3(x² + 3x - 3x - 9).
Let's factor.
3(x(x+3)-3(x+3))
<u>3(x-3)(x+3)</u>
There are multiple shortcuts which you could make here, FYI:
Instead of splitting the middle, if your a value is 1, you can go straight to that step (x+number)(x+other number).
Whenever you have a difference of squares, like a²-b², that factors to (a+b)(a-b).
5y - 5= 22
or
5(y)-5=22
Hope that helps!
U can see the answer in the picture below
Answer:
x ≥ -1/2
Step-by-step explanation:
We know that we cannot graph imaginary numbers. Therefore, our <em>x </em>value has to be greater than or equal to 0:
To find our domain, we need to set the square root equal to zero:
√(4x + 2) = 0
4x + 2 = 0
4x = -2
x = -1/2
We now know that no value below -1/2 can be used or we will get an imaginary number. Therefore, our answer is x ≥ -1/2
Alternatively, we can graph the function and analyze domain: