Answer:
31.78 grams
25.55%
Explanation:
The balanced reaction for ammonium chloride with calcium oxide will be:
2NH4Cl + Ca(OH)2 ---> CaCl2 + 2NH3 + 2H2O
The molecular weight for ammonium chloride(NH4Cl ) is 53.49g/mol, while the molecular weight for ammonium(NH3) is 17g/mol. The number of theoretical yield of ammonia from 100g of ammonium chloride will be:
100g / (53.49g/mol) * 2/2 * 17g/mol= 31.78 grams
If the actual yield is 8.12g, the percent yield will be: 8.12g/31.78g * 100% =25.55%
Arsenic, I believe. Metalloids fall in between metals and nonmetals (usually on the bold line separating the two on the periodic table). And since the metalloid in question has four electron shells and five valence electrons in the outermost shell, you can see that this element is arsenic
0.250 mol/L
<em>Step 1</em>. Write the chemical equation
H2SO4 + 2NaOH → Na2SO4 + 2H2O
<em>Step 2</em>. Calculate the moles of H2SO4
Moles of H2SO4 = 12.5 mL H2SO4 × (0.500 mmol H2SO4/1 mL H2SO4)
= 6.25 mmol H2SO4
<em>Step 3</em>. Calculate the moles of NaOH
Moles of NaOH = 6.25 mmol H2SO4 × (2 mmol NaOH/(1 mmol H2SO4)
= 12.5 mmol NaOH
<em>Step 4</em>. Calculate the concentration of the NaOH
[NaOH] = moles/litres = 12.5 mmol/50.0 mL = 0.250 mol/L
.....i don't understand the question sorry
Answer:
The answer to your question is:
Explanation:
1 mol = 6.022 x 10 ²³ atoms
755 moles = x
x = 755 x 6.022 x 10 ²³ / 1 = 4.54 x 10 ²⁶ atoms
