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3 years ago

Why are kelp forests considered important to our understanding of marine ecosystems?

2 answers:

7 0

A kelp forest is an ecosystem in itself. Many animals use these massive forests to shelter their young from predators. Other animals feed off of the kelp plants. When you understand how marine life lives with the kelp forests you can begin to understand the big picture.

LenKa [72]3 years ago

7 0

Answer:

<u>Kelp forest are an underwater biome, that cover about 25% of the surface of the world's coastlines. Example of Anacapa Island, California</u>

Explanation:

They are physically formed by microalgae. These forests provide unique habitats for marine organisms and hence are a source for understanding marine ecology. They are essential for <u>navigators and provide sustenance opportunities, recreational activities, and all ecosystem services. </u>

However these ecosystems re now degrading due to the impact of humans upon their environment. One such concern is the impact of overfishing. <u>Globally kelp forests are distributed around the world near the shorelines.</u>

Most of the kelp forest organisms have a gas-filled bladder that is usually located at the base of the fronds near the stripes. Which provides them buoyancy and helps maintain their upright position.

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The mass of .10 moles of iron is:

Stels [109]

Answer:

<em>so mass in gram=560grams</em>

Explanation:

number of moles=10moles

molar mass=56grams/moles

mass in gram of Fe=?

as we know that

$number of moles=\frac{mass in gram}{molar mass}$

<em>evaluating the formula</em>

<em>number of moles×molar mass=mass in gram</em>

<em>mass in gram=10moles×56grams/moles</em>

<em>mass in gram=560grams</em>

8 0

4 years ago

Read 2 more answers

Combustion analysis is performed on 0.50 g of a hydrocarbon, and 1.47 g of CO2 and 0.902 g of H2O are produced. What is the empi

JulijaS [17]

1. The empirical formula of the hydrocarbon is CH₃

2. The molecular formula of the hydrocarbon is C₂H₆

<h3>How to determine the mass of Carbon </h3>

Mass of CO₂ = 1.47 g
Molar mass of CO₂ = 44 g/mol
Molar of C = 12 g/mol
Mass of C =?

Mass of C = (12 / 44) × 1.47

Mass of C = 0.4 g

<h3>How to determine the mass of H</h3>

Mass of compound = 0.5 g
Mass of C = 0.4 g
Mass of H = ?

Mass of H = (mass of compound) – (mass of C)

Mass of H = 0.5 – 0.4

Mass of H =0.1 g

<h3>1. How to determine the empirical formula </h3>

C = 0.4 g
H = 0.1 g
Empirical formula =?

Divide by their molar mass

C = 0.4 / 12 = 0.03

H = 0.1 / 1 = 0.1

Divide by the smallest

C = 0.03 / 0.03 = 1

H = 0.1 / 0.03 = 3

Thus, the empirical formula of the compound is CH₃

<h3>2. How to determine the molecular formula</h3>

Empirical formula = CH₃
Molar mass = 30 g/mol
Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

Learn more about empirical formula:

brainly.com/question/24297883

#SPJ1

4 0

2 years ago

In a combustion reaction of C3H8 + 5O2 = 3CO2 + 4H2O, how do you know that the first compounds will produce the nuber of what th

katovenus [111]

To balance chemical equations, you should just remember that the number of atoms of an element in the reactant side must be equal to the number of atoms of the same element in the product side. The order of the substances doesn't matter. What is important that the equation balances.

3 0

3 years ago

What is the molarity of a solution that contains 122g of MgSO4 n 3.5L of solution?

tatiyna

Answer:

0.29mol/L or 0.29moldm⁻³

Explanation:

Given parameters:

Mass of MgSO₄ = 122g

Volume of solution = 3.5L

Molarity is simply the concentration of substances in a solution.

Molarity = number of moles/ Volume

>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.

Number of moles = mass/ molar mass

Molar mass of MgSO₄:

Atomic masses: Mg = 24g

S = 32g

O = 16g

Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol

= (24 + 32 + 64)g/mol

= 120g/mol

Number of moles = 122/120 = 1.02mol

>>>> From the given number of moles we can evaluate the Molarity using this equation:

Molarity = number of moles/ Volume

Molarity of MgSO₄ = 1.02mol/3.5L

= 0.29mol/L

IL = 1dm³

The Molarity of MgSO₄ = 0.29moldm⁻³

6 0

3 years ago

During your reaction, you added 0.3 mL concentrated H2SO4 (18.4 M) as the catalyst. At the end of the reaction, you need to add

sattari [20]

Answer:

58.72 mL

Explanation:

The chemical equation for the neutralization reaction is :

H₂SO₄(aq) + Na₂CO₃(s) --------------> Na₂SO₄(aq) + H₂O(l) + CO₂(g)

where;

M₁ = Molarity of H₂SO₄

M₂= Molarity of Na₂CO₃

V₁= Volume of H₂SO₄

V₂ = Volume of Na₂CO₃

Given that :

M₁ = 18.4 M

V₁= 0.3 mL

10% Na₂CO₃ means 100 g of solution contain 10 g of Na₂CO₃

i.e. 10 g Na₂CO₃ dissolved and diluted to 100 mL water.

Molar mass of Na₂CO₃ = 106 g/mol

106 g Na₂CO₃ dissolved in 100 mL will give 0.1 M Na₂CO₃ solution.

However;

If, 106 g Na₂CO₃ ≡ 0.1 M Na₂CO₃

Then, 10 g Na₂CO₃ ≡ 'A' M of Na₂CO₃

By cross multiplying; we have:

106 × A = 10 × 0.1

106 × A = 1

A = (1/106) M/100 mL

A = 10 x (1/106)) M/L

A = (10/106) M

A = 0.094 M

Therefore,the molarity of 10% Na₂CO₃ solution is 0.094 M.

For the Neutralization equation, we have:

M₁V₁ = M₂V₂

18.4×0.3 = 0.094×V₂

Making V₂ the subject of the formula;we have:

$V_2 = \frac{18.4*0.3}{0.094}$

V₂ = 58.72 mL

4 0

3 years ago